Question

我正在构建一个JSON对象，供DataTables子行选项使用，以显示各种客户的车道费率。我已经将这些数据收集到JSON对象中。

我一直在弄混这个js小提琴（http://jsfiddle.net/7v2Cs/1/）来尝试合并对象，但是由于它们使用不同的格式，因此并没有取得太大的成功。（基于以下问题：Combining Nested Objects in a JSON Array）

数据的格式如下：

  var cData = 
  [
     {
        "customer_name":"Company1",
        "type_of_shipment":"F",
        "pickup_city":"MARTINSBURG",
        "pickup_state":"WV",
        "consignee_city":"BALL GROUND",
        "consignee_state":"GA",
        "AVG( proj_revenue )":"1683.333333",
        "AVG( proj_gross_profit )":"216.666667",
        "COUNT( pro_num )":3
     },
     {
        "customer_name":"Company2",
        "type_of_shipment":"V",
        "pickup_city":"ALLENTOWN",
        "pickup_state":"PA",
        "consignee_city":"ROBBINSVILLE",
        "consignee_state":"NJ",
        "AVG( proj_revenue )":"572.320000",
        "AVG( proj_gross_profit )":"222.320000",
        "COUNT( pro_num )":2
     },
     {
        "customer_name":"Company2",
        "type_of_shipment":"V",
        "pickup_city":"BUENA PARK",
        "pickup_state":"CA",
        "consignee_city":"NEWARK",
        "consignee_state":"CA",
        "AVG( proj_revenue )":"1132.820000",
        "AVG( proj_gross_profit )":"-217.180000",
        "COUNT( pro_num )":1
     },
     {
        "customer_name":"Company3",
        "type_of_shipment":"V",
        "pickup_city":"BENSENVILLE",
        "pickup_state":"IL",
        "consignee_city":"STAUNTON",
        "consignee_state":"VA",
        "AVG( proj_revenue )":"3725.000000",
        "AVG( proj_gross_profit )":"1025.000000",
        "COUNT( pro_num )":2
     }
  ]

  var cData2 = [
     {
        "customer":"Company1",
        "shipments1":1,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00"
     },
     {
        "customer":"Company2",
        "shipments1":0,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00"

     },
     {
        "customer":"Company3",
        "shipments1":0,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00"
     }
  ]

想法是将数据格式化为：

  var cDataFinal = 
  [
     {
        "customer":"Company1",
        "shipments1":1,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00",
        "lanes":[
        {
              "customer_name":"Company1",
              "type_of_shipment":"F",
              "pickup_city":"MARTINSBURG",
              "pickup_state":"WV",
              "consignee_city":"BALL GROUND",
              "consignee_state":"GA",
              "AVG( proj_revenue )":"1683.333333",
              "AVG( proj_gross_profit )":"216.666667",
              "COUNT( pro_num )":3
        }]
     },
     {
        "customer":"Company2",
        "shipments1":0,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00",
        "lanes":[
        {
              "customer_name":"Company2",
              "type_of_shipment":"V",
              "pickup_city":"ALLENTOWN",
              "pickup_state":"PA",
              "consignee_city":"ROBBINSVILLE",
              "consignee_state":"NJ",
              "AVG( proj_revenue )":"572.320000",
              "AVG( proj_gross_profit )":"222.320000",
              "COUNT( pro_num )":2
        },
        {
              "customer_name":"Company2",
              "type_of_shipment":"V",
              "pickup_city":"BUENA PARK",
              "pickup_state":"CA",
              "consignee_city":"NEWARK",
              "consignee_state":"CA",
              "AVG( proj_revenue )":"1132.820000",
              "AVG( proj_gross_profit )":"-217.180000",
              "COUNT( pro_num )":1
        }]
     },
     {
        "customer":"Company3",
        "shipments1":0,
        "profit1":"0.00",
        "gp_percent1":"0.0000",
        "agp1":"0.00",
        "lanes":[
        {
              "customer_name":"Company3",
              "type_of_shipment":"V",
              "pickup_city":"BENSENVILLE",
              "pickup_state":"IL",
              "consignee_city":"STAUNTON",
              "consignee_state":"VA",
              "AVG( proj_revenue )":"3725.000000",
              "AVG( proj_gross_profit )":"1025.000000",
              "COUNT( pro_num )":2
        }]
     }
  ]

是否有任何建议或可用的工具来合并两个字段相似的JSON对象，并将一组数据作为子集插入？

Answer 1

您可能不需要考虑合并。您只需要遍历一个数组并添加一个属性即可。

您可以尝试这样的事情：

public String goAdd(Model model) {
    model.addAttribute(new DtoCustomer());
    return "customer/edit";
}

Answer 2

您可以简单地根据customer_name过滤cData并将其添加到cData2中的lanes属性。

var mergedData =   cData2.map(data2 => {
   const filterData = cData.filter(cData => {  return cData.customer_name === data2.customer })
   data2.lanes = filterData;
   return data2;
});

希望这会有所帮助

如何合并两个JSON对象，将一组数据附加为另一组数据的子对象？

2 个答案: