Question

我有两个JSON文件：

JSON 1

{
  "title": "This is a title",
  "person" : {
    "firstName" : "John",
    "lastName" : "Doe"
  },
  "cities":[ "london", "paris" ]
}

JSON 2

{
  "title": "This is another title",
  "person" : {
    "firstName" : "Jane"
  },
  "cities":[ "colombo" ]
}

我想将＃2合并到＃1，其中＃2覆盖＃1，产生以下输出：

{
  "title": "This is another title",
  "person" : {
    "firstName" : "Jane",
    "lastName" : "Doe"
  },
  "cities":[ "colombo" ]
}

我检查了执行此操作的crate json-patch，但它不能针对稳定的Rust进行编译。是否有可能做类似serde_json和稳定的Rust？

之类的事情

Answer 1

将Shepmaster建议的答案放在

下面

#[macro_use]
extern crate serde_json;

use serde_json::Value;

fn merge(a: &mut Value, b: Value) {
    match (a, b) {
        (a @ &mut Value::Object(_), Value::Object(b)) => {
            let a = a.as_object_mut().unwrap();
            for (k, v) in b {
                merge(a.entry(k).or_insert(Value::Null), v);
            }
        }
        (a, b) => *a = b,
    }
}

fn main() {
    let mut a = json!({
        "title": "This is a title",
        "person" : {
            "firstName" : "John",
            "lastName" : "Doe"
        },
        "cities":[ "london", "paris" ]
    });

    let b = json!({
        "title": "This is another title",
        "person" : {
            "firstName" : "Jane"
        },
        "cities":[ "colombo" ]
    });

    merge(&mut a, b);
    println!("{:#}", a);
}

Answer 2

这对我有用

#[macro_use]
extern crate serde_json;

use serde_json::Value;

fn merge(a: &mut Value, b: &Value) {
    match (a, b) {
        (&mut Value::Object(ref mut a), &Value::Object(ref b)) => {
            for (k, v) in b {
                merge(a.entry(k.clone()).or_insert(Value::Null), v);
            }
        }
        (a, b) => {
            *a = b.clone();
        }
    }
}

fn main() {
    let mut a = json!({
        "title": "This is a title",
        "person" : {
            "firstName" : "John",
            "lastName" : "Doe"
        },
        "cities":[ "london", "paris" ]
    });

    let b = json!({
        "title": "This is another title",
        "person" : {
            "firstName" : "Jane"
        },
        "cities":[ "colombo" ]
    });

    merge(&mut a, &b);
    println!("{:#}", a);
}

Answer 3

由于您想使用json-patch，因此我假设您正在专门寻找crate实现的JSON Merge Patch (RFC 7396)实现。在这种情况下，合并对象应该取消设置其补丁中的对应值为null的那些键，而其他答案中的代码示例将不实现这些键。

解释该问题的代码如下。我通过将补丁设置为person.lastName来修改补丁程序以删除null键。它还不需要unwrap() Option返回的as_object_mut()。

#[macro_use]
extern crate serde_json;

use serde_json::Value;

fn merge(a: &mut Value, b: Value) {
    if let Value::Object(a) = a {
        if let Value::Object(b) = b {
            for (k, v) in b {
                if v.is_null() {
                    a.remove(&k);
                }
                else {
                    merge(a.entry(k).or_insert(Value::Null), v);
                }
            } 

            return;
        }
    }

    *a = b;
}

fn main() {
    let mut a = json!({
        "title": "This is a title",
        "person" : {
            "firstName" : "John",
            "lastName" : "Doe"
        },
        "cities":[ "london", "paris" ]
    });

    let b = json!({
        "title": "This is another title",
        "person" : {
            "firstName" : "Jane",
            "lastName": null
        },
        "cities":[ "colombo" ]
    });

    merge(&mut a, b);
    println!("{:#}", a);
}

预期输出为

{
  "cities": [
    "colombo"
  ],
  "person": {
    "firstName": "Jane"
  },
  "title": "This is a title"
}

通知person.lastName尚未设置。

如何将两个JSON对象与Rust合并？

3 个答案: