Question

我需要将两列中包含相似项目的行汇总在一起。请问有一个“或”功能可以做到这一点吗？我在下面发布了一个样本数据集：

def get(self, request, task_id): 
    ...

如何进行汇总，以使我只得到一个值，将第3行和第5行的频率组合在一起，其中Animal1是B，Animal2是D在第3行，Animal1是D，Animal2是B在第5行给出频率为6？

Answer 1

这是一个可能的解决方案。我可能使它复杂化了，但是它应该给您想要的结果。我要做的第一件事是使字符串成为数据帧中的因素。

A1 <- data.frame(Animal1= c("A", "A","B","B","D"), Animal2=c("B","D","D","A","B"), 
                 Frequency=c(2,3,1,4,5), stringsAsFactors = FALSE) 

A1 %>% 
  mutate(combined = map2_chr(Animal1, Animal2, ~paste0(sort(c(.x, .y)), collapse = ""))) %>%  
  group_by(combined) %>% 
  summarise(total = sum(Frequency))

输出

# A tibble: 3 x 2
  combined total
  <chr>    <dbl>
1 AB           6
2 AD           3
3 BD           6

Answer 2

我不确定我是否理解您的问题，但这是您要寻找的吗？

library(dplyr)
df %>% as_tibble %>% 
  filter((Animal1 == "B" & Animal2 == "D") | (Animal1 == "D" & Animal2 == "B")) %>% 
  summarise(sum_freq = sum(Frequency))

Answer 3

谢谢，伙计们。除了@StephenK的答案外，我还增加了一个步骤来拆分新的“组合”列。

A1 <- data.frame(Animal1= c("A", "A","B","B","D"), Animal2=c("B","D","D","A","B"), 
             Frequency=c(2,3,1,4,5), stringsAsFactors = FALSE) 

A2<- as.data.frame(A1 %>% mutate(combined = map2_chr(Animal1, Animal2, ~paste0(sort(c(.x, .y)), collapse = ""))) %>%  
group_by(combined) %>% summarise(total = sum(Frequency)))

#create new columns for each letter
A2$Animal1 <- substr(A2$combined, start = 1, stop = 1)
A2$Animal2 <- substr(A2$combined, start = 2, stop = 2)
A2
  combined total Animal1 Animal2
1       AB     6       A       B
2       AD     3       A       D
3       BD     6       B       D

##Select only columns needed and reorder
A3 <- A2[,c("Animal1","Animal2", "total")]
A3
  Animal1 Animal2 total
1       A       B     6
2       A       D     3
3       B       D     6

在R中具有相似向量的两列的基础上对一列项目进行汇总或汇总

3 个答案: