这是给你的。
为什么这个不编译
REPORT ZZY.
TYPES: my_int TYPE x LENGTH 4,
my_int_table TYPE STANDARD TABLE OF my_int WITH EMPTY KEY.
DATA(g_tab_my_int) = VALUE my_int_table( ( 2 ) ).
这是吗？
REPORT ZZY.
TYPES: my_int TYPE x LENGTH 4,
my_int_table TYPE STANDARD TABLE OF my_int WITH EMPTY KEY.
DATA(g_tab_my_int) = VALUE my_int_table( ( 2 * 1 ) ).
答案 0 :(得分：7)
const toogleCheckbox = event => {
let treeNode = event.target.parentNode.parentNode;
let button = document.getElementById('buttonWrap');
if (treeNode) {
button.classList.add("show")
treeNode.nodeData.isSelected = !treeNode.nodeData.isSelected;
toggleChildren(treeNode.childNodes, treeNode.nodeData.isSelected);
if (treeNode.pNode) {
checkParent(treeNode.pNode);
}
}
};
const checkParent = node => {
let checks = node.nodeData.children.length;
let intermidiateNode = node.children[0].getElementsByTagName("input")[0];
let checksActive = node.nodeData.children.filter(cNode => {
return cNode.isSelected == true;
}).length;
if (checks == checksActive) {
node.nodeData.isSelected = true;
intermidiateNode.indeterminate = false;
}
else if (checksActive > 0) {
intermidiateNode.indeterminate = true;
}
else {
node.nodeData.isSelected = false;
intermidiateNode.indeterminate = false;
}
node.querySelector("input.tree-view__checkbox").checked = node.nodeData.isSelected;
if (node.pNode) {
checkParent(node.pNode);
}
};
const toggleChildren = (children, state) => {
for (let node = 0; node < children.length; node++) {
if (children[node].type == "checkbox") {
let parent = children[node].parentNode.parentNode;
parent.nodeData.isSelected = state;
children[node].checked = state;
}
toggleChildren(children[node].childNodes, state);
}
};
内部的ABAP documentation说：
如果为
VALUE dtype|#( line | {LINES OF itab ...} )指定了数据对象，则该对象必须与行类型兼容。如果为
line指定了一个表达式（内置函数，函数方法，计算表达式，构造函数表达式或表表达式），则该表达式的结果必须可转换为行类型。
在您的示例中：
您可以输入一个较短的表达式，例如“ + 2”：line