Question

Errr可以帮助我解决这个问题。当我尝试运行代码时，我收到此错误：EOL扫描字符串文字时?????????

这是我的代码（它是游戏的主菜单）：

bif="menubg.jpg"
load_check_x = "null"
load_check_y = "null"
import pygame, sys
from pygame.locals import *
x = 0
y = 0

pygame.init()
screen=pygame.display.set_mode((640,360),0,32)
background=pygame.image.load(bif).convert()
screen.fill(BLACK)

class MainWindow:
  def __init__(self,screen):
         new_text = menu_font.render('Play!!!!', 1, (100, 100, 100))
         screen.blit(new_text, (340, 425))
         while True:

             evc = pygame.event.get()

             x,y = pygame.mouse.get_pos()
             #Setup mouse pos!!!
             if x >= 340 and x <= 465:
                load_check_x = "True"
             if x < 340 or x > 465:
                load_check_x = "False"

             if y >= 425 and y <= 445:
                load_check_y = "True"
             if y < 425 or y > 445:
                load_check_y = "False"

             if load_check_x == "True" and load_check_y == "True:
                for event.type == pygame.MOUSEBUTTONUP:
                    clear()

 def clear():
     screen.fill(BLACK)

Answer 1

正如语法高亮显示的那样，您忘记了上一个if语句中的结束双引号。

if load_check_x == "True" and load_check_y == "True:

应该是......

if load_check_x == "True" and load_check_y == "True":

EOL在扫描字符串文字时，Python Pygame语法错误？

1 个答案: