Question

我想将Tagless Final的F＃OOP version转换为典型的FP方法，并且我想使用Statically Resolved Type Parameters中的Type Classes from OO。

我所做的是

open System
open FSharpPlus

type UserName = string
type DataResult<'t> = DataResult of 't with
    static member Map ( x:DataResult<'t>  , f) =
        match x with 
        | DataResult t -> DataResult (f t)

创建我需要的SRTP

type Cache = 
    static member inline getOfCache cacheImpl data =
        ( ^T : (member getFromCache : 't -> DataResult<'t> option) (cacheImpl, data))
    static member inline storeOfCache cacheImpl data =
        ( ^T : (member storeToCache : 't -> unit) (cacheImpl, data))

type DataSource() =
    static member inline getOfSource dataSourceImpl data =
        ( ^T : (member getFromSource : 't -> DataResult<'t>) (dataSourceImpl, data))
    static member inline storeOfSource dataSourceImpl data =
        ( ^T : (member storeToSource : 't -> unit) (dataSourceImpl, data))

及其具体实现方式

type CacheNotInCache() = 
        member this.getFromCache _ = None
        member this.storeCache _ = () 

type CacheInCache() =
        member this.getFromCache user = monad { 
           return! DataResult user |> Some}
        member this.storeCache _ = () 

type  DataSourceNotInCache() = 
          member this.getFromSource user = monad { 
               return! DataResult user } 

type  DataSourceInCache()  =
          member this.getFromSource _  = 
              raise (NotImplementedException())

通过它可以定义无标签的最终DSL

let requestData (cacheImpl: ^Cache) (dataSourceImpl: ^DataSource) (userName:UserName) = monad {
    match Cache.getOfCache cacheImpl userName with
    | Some dataResult -> 
            return! map ((+) "cache: ") dataResult
    | None -> 
            return! map ((+) "source: ") (DataSource.getOfSource dataSourceImpl userName) }

这样的工作如下

[<EntryPoint>]
let main argv =
    let cacheImpl1 = CacheInCache() 
    let dataSourceImpl1 = DataSourceInCache()
    let cacheImpl2 = CacheNotInCache() 
    let dataSourceImpl2 = DataSourceNotInCache()
    requestData cacheImpl1 dataSourceImpl1 "john" |> printfn "%A"
    //requestData (cacheImpl2 ) dataSourceImpl2 "john" |> printfn "%A"
    0

问题是我收到警告

construct导致代码的通用性低于类型指示的通用性注释

同时用于cacheImpl1和dataSourceImpl1，因此在其他情况下我无法重用requestData。有没有办法绕开这个问题？

Answer 1

我对您要实现的抽象并不熟悉，但是在查看代码时，您似乎在这里缺少了inline修饰符：

let inline requestData (cacheImpl: ^Cache) (dataSourceImpl: ^DataSource) (userName:UserName) = monad {
    match Cache.getOfCache cacheImpl userName with
    | Some dataResult -> 
            return! map ((+) "cache: ") dataResult
    | None -> 
            return! map ((+) "source: ") (DataSource.getOfSource dataSourceImpl userName) }

请注意，您可以像这样简化地图功能：

type DataResult<'t> = DataResult of 't with
    static member Map (DataResult t, f) = DataResult (f t)

Answer 2

我熟悉最终的无标签，但是我不确定为什么要使用SRTP。最终的无标记使用类型类，并且可以使用接口对其进行仿真（请参见scala仿真类型类的方式）。

该方法与“对象代数”相似（基本上相同），可以使用标准的OO构造来实现。

使用SRTP在F＃中实现无标签最终编码

2 个答案: