Question

当有编号的数组时，引用数组中第一个元素的正确语法是什么？

someArray1["someString", "anotherString"];
someArray2["someString", "anotherString"];
someArray3["someString", "anotherString"];

heresANumber = 1;
grabAString(heresANumber);

function grabAString(theNumber){
    var string = 'someArray' + theNumber[0].slice(0,1);
}

是否有一种简单的方法指向顺序编号的数组？

Answer 1

您可以对订购的商品进行数组处理。

function grabAString(theNumber){
    return array[theNumber - 1];
}

var someArray1 = ["someString", "anotherString"],
    someArray2 = ["someString", "anotherString"],
    someArray3 = ["someString", "anotherString"],
    array = [someArray1, someArray2, someArray3],
    heresANumber = 1;

console.log(grabAString(heresANumber));

高级版本采用一个从零开始的索引，例如

0, ..., n - 1

并通过索引直接访问。

另一种解决方案是将short hand properties放在变量名称为属性的对象中。这样可以使用组合键进行访问。

function grabAString(theNumber){
    return object['someArray' + theNumber];
}

var someArray1 = ["someString", "anotherString"],
    someArray2 = ["someString", "anotherString"],
    someArray3 = ["someString", "anotherString"],
    object = { someArray1, someArray2, someArray3 },
    heresANumber = 1;

console.log(grabAString(heresANumber));

Answer 2

将这些数组分配为对象的属性，以便可以对动态属性名称使用[]表示法

const arrs = {
  someArray1 : ["someString", "anotherString"],
  someArray2 : ["someString", "anotherString"],
  someArray3 : ["someString", "anotherString"]

}
heresANumber = 1;


function grabAString(theNumber) {
  return arrs['someArray' + theNumber][0];
}

console.log( grabAString(heresANumber))

引用数组语法的javascript

2 个答案: