我这里有一个文本文件,带有两个值,一个名称和一个分数。 我有一个具有4个成员的学生结构,如下所示。
我正在寻找将文本文件中的值添加到结构中以逗号分隔的相应成员的方法。
students.txt文件的前五行;
Nubia,Dufrene,70
Louisa,Trippe,49
Aline,Deniz,34
Shery,Munk,63
Angila,Ping,89
我当前的代码;
struct studentType {
string studentFName;
string studentLName;
int testScore;
char grade;
};
int main()
{
vector<studentType> studentVector;
studentType student;
ifstream inFile("students.txt");
while (getline(inFile, student.studentFName, ',' )) {
cout << student.studentFName << endl;
}
printStudents(studentVector);
}
void printStudents(vector<studentType>& passedVect) {
for (studentType element : passedVect) {
cout << element.studentFName << " " << element.studentLName << "\tGrade: " << element.testScore << " (" << element.grade << ")" << endl;
}
}
FIX 我已将for循环替换为while循环。 我还必须将结构从int更改为string才能与getline一起使用。简单的convertString函数使用std :: stoi将其转换回最初计划的int值。
int main()
{
vector<studentType> studentVector;
studentType student;
ifstream inFile("students.txt");
for (studentType i;
getline(inFile, i.studentFName, ',')
&& getline(inFile, i.studentLName, ',')
&& getline(inFile, i.testScore)
; )
{
int testScore = convertString(i.testScore);
i.grade = assignGrade(testScore);
studentVector.push_back(i);
}
printStudents(studentVector);
}
int convertString(string number) {
return stoi(number);
}
输出
Struct Exercises!
Nubia Dufrene Grade: 70 (B)
Louisa Trippe Grade: 49 (D)
Aline Deniz Grade: 34 (F)
Shery Munk Grade: 63 (C)
Angila Ping Grade: 89 (A)
Laila Hollmann Grade: 10 (F)
Sherrill Piller Grade: 47 (D)
Minna Dimitri Grade: 26 (F)
Song Kornreich Grade: 97 (A)
Frank Dammann Grade: 36 (F)
Isaac Abee Grade: 24 (F)
Tiffaney Lukach Grade: 75 (B)
Carmelina Sink Grade: 85 (A)
Matthew Benes Grade: 34 (F)
Fleter Aichele Grade: 78 (B)
Sergio Ewan Grade: 56 (C)
Izetta Armes Grade: 42 (D)
Olen Tee Grade: 89 (A)
Leona Mozee Grade: 54 (D)
Britta Pegrast Grade: 34 (F)
再次感谢!
答案 0 :(得分:0)
您可以使用std::stringstream
首先保存每一行,然后使用相同的策略
getline(inFile, student.studentFName, ',' )
除了现在在stringstream上填充3个变量。现在,学生已填满,您可以将push_back
插入vector
中,然后调用printStudents
函数。
我删除了using namespace std;
,因为这是错误的做法(您可以阅读here的原因)。您还没有在文本文件中提供grade
,因此在打印学生时我删除了该部分。
#include <string>
#include <fstream>
#include <iostream>
#include <vector>
#include <sstream> //std::stringstream
struct studentType {
std::string studentFName;
std::string studentLName;
int testScore;
char grade;
};
void printStudents(const std::vector<studentType>& passedVect) { //also: const&!
for (studentType element : passedVect) {
std::cout << element.studentFName << " " << element.studentLName << "\tScore: " << element.testScore << '\n';
}
}
int main() {
std::vector<studentType> studentVector;
studentType student;
std::ifstream inFile("students.txt");
if (!inFile.good()) {
std::cerr << "couldn't find student.txt file\n";
return -1;
}
std::string line;
while (std::getline(inFile, line)) {
std::stringstream stream(line);
std::getline(stream, student.studentFName, ','); //get first name
std::getline(stream, student.studentLName, ','); //get last name
std::string score_str; //since testScore is an int, first save it as a string
std::getline(stream, score_str, ',');
student.testScore = std::stoi(score_str); //convert string to int
studentVector.push_back(student); //push it into vector
}
printStudents(studentVector);
}
输出:
Nubia Dufrene Score: 70
Louisa Trippe Score: 49
Aline Deniz Score: 34
Shery Munk Score: 63
Angila Ping Score: 89
答案 1 :(得分:0)
struct studentType {
string studentFName;
string studentLName;
string testScore;
char grade;
};
void printStudents(vector<studentType>& passedVect );
int main()
{
vector<studentType> studentVector;
studentType student;
ifstream inFile("students.txt");
while (getline(inFile, student.studentFName, ',' )
&& getline(inFile, student.studentLName, ',')
&& getline(inFile, student.testScore) ) {
cout << student.studentFName << " "
<< student.studentLName << " "
<< student.testScore << endl;
}
}
我只是将它们收成空,并将testScore更改为字符串