试图使用递归来显示int数组的排列,但是由于某种原因,当我调用该函数时,它不会显示任何内容。我缺少的主要功能中有东西吗?
public static void Permutation(int[] a, int prefix) {
int length = a.length;
if (length == prefix) {
printArray(a);
}
else {
for (int i = 0; i < prefix; i++) {
swap(a, prefix, i);
Permutation(a, prefix + 1);
swap(a, prefix, i);
}
}
}
public static void swap(int[] a, int x, int y) {
int z = a[x];
a[x] = a[y];
a[y] = z;
}
public static void printArray(int[] thing) {
System.out.println("\n");
for (int x = 0; x < thing.length; x++)
System.out.print(thing[x]);
}
public static void main(String[] args) {
int a[] = { 1, 2, 3 };
Permutation(a, 0);
}
说我有一个1、2和3的int数组。输出应该是
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
答案 0 :(得分:0)
查看您的for循环并分析程序:)
$messages = $mysqli->query('SELECT `message` FROM `history` LIMIT 0,100;');
while($row = $messages->fetch_array(MYSQLI_ASSOC)) {
$msg = $row['message'];
$result2 = $mysqli->query(
'SELECT `id` FROM `messages` WHERE `message` = "'.$msg.'" LIMIT 0,1'
);
$row2 = $result2->fetch_array(MYSQLI_ASSOC);
$id = $row2['id'];
$mysqli->query(
'UPDATE `history` SET `message`="'.$id.'" WHERE `message` = "'.$msg.'"'
);
$result2->free_result();
}