Question

我如何测试onclick的子组件。

请参见下面的代码段。

// App.js

import React, {Component, Fragment} from 'react'
import Child from './child'

class App extends Component{

  state = {
    data: null,
    enable: false
  }

  componentDidMount(){
    this.getData()
  }

  getData = async () => {
    const response = await fetch('http://www.example.com');
    const data = await response.json();
    this.setState({
      data
    })
  }

  _handleChildClick = () => {
    this.setState({
      enable: true
    })
  }

  render(){
    const {data, enable} = this.state
    if(!data){
      return (
       <div>
         Loading
       </div>
      )
    }else{
      <Fragment>
        <Child
         handleChildClick={this._handleChildClick}
        />
      </Fragment>
    }
  }
}


export default App


import React from 'react';

const child = () => {
  return(
    <div>
      <button
        className="toggle"
        onClick={props.handleChildClick}
      >
      Toggle
      </button>
    </div>
  )
}

export default child

// App.test.js

import React from 'react';
import {enzyme} from 'enzyme';
import App from './App';

describe("App test cases", () => {
  it('should trigger _handleChildClick', async () => {
    window.fetch = jest.fn().mockImplementation(() => ({
      status: 200,
      json: () => new Promise((resolve, reject) => {
        resolve(
            {
              name: "some data"
            }
        )
      })
    })) 
    const mountWrapper = await mount(<App />)
    setTimeout(() => {
       mountWrapper.update()
             const SpyhandleChildClick = jest.spyOn(mountWrapper.instance(),'_handleChildClick')
      mountWrapper.find('.toggle').simulate('click')
      expect(SpyhandleChildClick).toHaveBeenCalled() // not called 
    },0)
  })
})

Answer 1

一些要考虑的重点。

测试中的异步代码

如果您必须在测试中执行异步任务，则必须始终等待异步内容完成。

setTimeout(() => {
   mountWrapper.update()
         const SpyhandleChildClick = jest.spyOn(mountWrapper.instance(),'_handleChildClick')
  mountWrapper.find('.toggle').simulate('click')
  expect(SpyhandleChildClick).toHaveBeenCalled() // not called 
},0)

在代码中，您有一个超时段。此代码块中的任何测试条件都不会被评估，因为由于异步特性，到评估它们时，您的“测试会话”已经结束。

在带有酶的React中测试箭头功能-forceUpdate（）

酶库似乎存在问题，您必须在侦查反应成分以使其锁定到方法后强制更新反应成分。请关注github问题以获取更多信息：https://github.com/airbnb/enzyme/issues/365

我还整理了一下您的测试代码，使其更易于理解！

// App.test.js

import React from 'react';
import {enzyme} from 'enzyme';
import App from './App';


describe("App test cases", () => {
  it("should trigger _handleChildClick", async () => {
    window.fetch = jest.fn().mockImplementation(() => ({
      status: 200,
      json: () =>
        new Promise((resolve, reject) => {
          resolve({
            name: "some data"
          });
        })
    }));

    const mountWrapper = mount(<App />);
    mountWrapper.update();
    console.log("mountWrapper", mountWrapper.debug()); // showing the loader one

    //[FIX]This code will block and wait for your asynchronous tasks to be completed
    await new Promise(res => setTimeout(() => res(), 0));

    mountWrapper.update();
    console.log("mountWrapper", mountWrapper.debug()); // nothing showing
    expect(mountWrapper.find(".toggle").length).toEqual(1);

    //[FIX]Get a reference from the wrapper and force update after the spyOn call
    const instance = mountWrapper.instance();
    const spy = jest.spyOn(instance, "_handleChildClick");
    instance.forceUpdate();

    mountWrapper.find(".toggle").simulate("click");

    expect(spy).toHaveBeenCalled();
  });
});

实时演示链接：单击浏览器上的“测试”选项卡以查看测试结果 https://codesandbox.io/s/mz21kpm37j

在箭头功能上进行测试时，酶onclick间谍toHaveBeenCalled测试不起作用

1 个答案: