我正在尝试使用Python将电子邮件发送给收件人列表,但被告知先连接。
import smtplib
try:
s = smtplib.SMTP('smtp.xxx.com', 587)
s.starttls()
s.login('barbaramilleraz@xxx.com', 'xxx')
message = '''
...message text...
'''
s.connect()
with open('players.txt') as f:
email = f.readlines()
email = [e.strip() for e in email]
for person in range(len(email)):
print('Sending email to {}'.format(email[person]))
s.sendmail('barbaramilleraz', email[person], message)
except(smtplib.SMTPSenderRefused):
pass
输出为:
C:\Users\BMiller>python mailing.py
Sending email xxx@xxx.com
Sending email to xxx@xxx.com
Traceback (most recent call last):
File "mailing.py", line 25, in <module>
s.sendmail('barbaramilleraz', email[person], message)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 852, in sendmail
self.ehlo_or_helo_if_needed()
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 600, in ehlo_or_helo_if_needed
if not (200 <= self.ehlo()[0] <= 299):
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 440, in ehlo
self.putcmd(self.ehlo_msg, name or self.local_hostname)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 367, in putcmd
self.send(str)
File "C:\Users\BMiller\AppData\Local\Programs\Python\Python37\lib\smtplib.py", line 359, in send
raise SMTPServerDisconnected('please run connect() first')
smtplib.SMTPServerDisconnected: please run connect() first
我是Python的新手,所以不确定如何继续。
谢谢。
答案 0 :(得分:0)
如dcg在评论中所述,您必须在发送电子邮件之前致电s.connect()
建立连接。
您提到的是,每次发送仅发送一次:这是因为发送每条消息后您正在呼叫s.quit()
。完成此操作后,s
对于所有意图和目的都是无效的:如果要再次使用它,则必须重新启动配置。
因此,在发送所有消息之前,请先致电s.connect()
,直到完全完成s.quit()
为止,才致电s
。
答案 1 :(得分:0)
如果想法是在引发异常时跳过收件人,则异常处理应该围绕地址循环内的sendmail调用进行。
for person in range(len(email)):
print('Sending email to {}'.format(email[person]))
try:
s.sendmail('barbaramilleraz', email[person], message)
except(smtplib.SMTPSenderRefused):
print('Sender Refused for {}'.format(email[person]))
continue