我正在使用以下方法使用SMTP从Python发送邮件。这是正确的使用方法还是我遗失了？
from smtplib import SMTP
import datetime
debuglevel = 0
smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
from_addr = "John Doe <john@doe.net>"
to_addr = "foo@bar.com"
subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )
message_text = "Hello\nThis is a mail from your server\n\nBye\n"
msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s"
% ( from_addr, to_addr, subj, date, message_text )
smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()
答案 0 :(得分：105)
我使用的脚本非常相似;我在这里发布它作为如何使用电子邮件。*模块生成MIME消息的示例;因此可以轻松修改此脚本以附加图片等。
我依靠我的ISP添加日期时间标题。
我的ISP要求我使用安全的smtp连接发送邮件，我依靠smtplib模块（可在http://www1.cs.columbia.edu/~db2501/ssmtplib.py下载）
在脚本中，用于在SMTP服务器上进行身份验证的用户名和密码（下面给出的虚拟值）在源中以纯文本形式显示。这是一个安全漏洞;但最好的选择取决于你需要多少小心（想要？）来保护这些。
=======================================
#! /usr/local/bin/python
SMTPserver = 'smtp.att.yahoo.com'
sender = 'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']
USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"
# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'
content="""\
Test message
"""
subject="Sent from Python"
import sys
import os
import re
from smtplib import SMTP_SSL as SMTP # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP # use this for standard SMTP protocol (port 25, no encryption)
# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText
try:
msg = MIMEText(content, text_subtype)
msg['Subject']= subject
msg['From'] = sender # some SMTP servers will do this automatically, not all
conn = SMTP(SMTPserver)
conn.set_debuglevel(False)
conn.login(USERNAME, PASSWORD)
try:
conn.sendmail(sender, destination, msg.as_string())
finally:
conn.quit()
except:
sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message
答案 1 :(得分：79)
我常用的方法......差别不大但有点
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))
mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')
mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())
mailserver.quit()
就是这样
答案 2 :(得分：21)
此外，如果您想使用TLS而不是SSL执行smtp auth，那么您只需更改端口（使用587）并执行smtp.starttls（）。这对我有用：
...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
...
答案 3 :(得分：6)
我看到的主要问题是你没有处理任何错误：.login（）和.sendmail（）都记录了他们可以抛出的异常，似乎.connect（）必须有一些方法来指示它无法连接 - 可能是底层套接字代码抛出的异常。
答案 4 :(得分：5)
确保您没有阻止SMTP的防火墙。我第一次尝试发送电子邮件时，Windows防火墙和迈克菲都阻止了它 - 永远都找不到它们。
答案 5 :(得分：5)
这个怎么样？
import smtplib
SERVER = "localhost"
FROM = "sender@example.com"
TO = ["user@example.com"] # must be a list
SUBJECT = "Hello!"
TEXT = "This message was sent with Python's smtplib."
# Prepare actual message
message = """\
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
# Send the mail
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
答案 6 :(得分：5)
以下代码对我来说工作正常：
import smtplib
to = 'mkyong2002@yahoo.com'
gmail_user = 'mkyong2002@gmail.com'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()
参考：http://www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/
答案 7 :(得分：3)
您应确保以正确的格式格式化日期 - RFC2822。
答案 8 :(得分：2)
查看所有那些长长的答案？请允许我通过几行来完成自我推销。
导入和连接：
import yagmail
yag = yagmail.SMTP('john@doe.net', host = 'YOUR.MAIL.SERVER', port = 26)
然后它只是一个单行：
yag.send('foo@bar.com', 'hello', 'Hello\nThis is a mail from your server\n\nBye\n')
当它超出范围时（或可以手动关闭）它实际上会关闭。此外，它允许您在密钥环中注册您的用户名，这样您就不必在脚本中写出密码（在撰写yagmail之前，这确实困扰了我！）
答案 9 :(得分：2)
我使用SMTP发送邮件的示例代码。
import smtplib, ssl
smtp_server = "smtp.gmail.com"
port = 587 # For starttls
sender_email = "sender@email"
receiver_email = "receiver@email"
password = "<your password here>"
message = """ Subject: Hi there
This message is sent from Python."""
# Create a secure SSL context
context = ssl.create_default_context()
# Try to log in to server and send email
server = smtplib.SMTP(smtp_server,port)
try:
server.ehlo() # Can be omitted
server.starttls(context=context) # Secure the connection
server.ehlo() # Can be omitted
server.login(sender_email, password)
server.sendmail(sender_email, receiver_email, message)
except Exception as e:
# Print any error messages to stdout
print(e)
finally:
server.quit()
答案 10 :(得分：1)
或
import smtplib
from email.message import EmailMessage
from getpass import getpass
password = getpass()
message = EmailMessage()
message.set_content('Message content here')
message['Subject'] = 'Your subject here'
message['From'] = "USERNAME@DOMAIN"
message['To'] = "you@mail.com"
try:
smtp_server = None
smtp_server = smtplib.SMTP("YOUR.MAIL.SERVER", 587)
smtp_server.ehlo()
smtp_server.starttls()
smtp_server.ehlo()
smtp_server.login("USERNAME@DOMAIN", password)
smtp_server.send_message(message)
except Exception as e:
print("Error: ", str(e))
finally:
if smtp_server is not None:
smtp_server.quit()
如果您想使用端口 465，您必须创建一个 SMTP_SSL 对象。
答案 11 :(得分：0)
你可以这样做
import smtplib
from email.mime.text import MIMEText
from email.header import Header
server = smtplib.SMTP('mail.servername.com', 25)
server.ehlo()
server.starttls()
server.login('username', 'password')
from = 'me@servername.com'
to = 'mygfriend@servername.com'
body = 'That A Message For My Girl Friend For tell Him If We will go to eat Something This Nigth'
subject = 'Invite to A Diner'
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
message = msg.as_string()
server.sendmail(from, to, message)
答案 12 :(得分：0)
这是Python 3.x的有效示例
#!/usr/bin/env python3
from email.message import EmailMessage
from getpass import getpass
from smtplib import SMTP_SSL
from sys import exit
smtp_server = 'smtp.gmail.com'
username = 'your_email_address@gmail.com'
password = getpass('Enter Gmail password: ')
sender = 'your_email_address@gmail.com'
destination = 'recipient_email_address@gmail.com'
subject = 'Sent from Python 3.x'
content = 'Hello! This was sent to you via Python 3.x!'
# Create a text/plain message
msg = EmailMessage()
msg.set_content(content)
msg['Subject'] = subject
msg['From'] = sender
msg['To'] = destination
try:
s = SMTP_SSL(smtp_server)
s.login(username, password)
try:
s.send_message(msg)
finally:
s.quit()
except Exception as E:
exit('Mail failed: {}'.format(str(E)))
答案 13 :(得分：0)
基于this example，我实现了以下功能：
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
def send_email(host, port, user, pwd, recipients, subject, body, html=None, from_=None):
""" copied and adapted from
https://stackoverflow.com/questions/10147455/how-to-send-an-email-with-gmail-as-provider-using-python#12424439
returns None if all ok, but if problem then returns exception object
"""
PORT_LIST = (25, 587, 465)
FROM = from_ if from_ else user
TO = recipients if isinstance(recipients, (list, tuple)) else [recipients]
SUBJECT = subject
TEXT = body.encode("utf8") if isinstance(body, unicode) else body
HTML = html.encode("utf8") if isinstance(html, unicode) else html
if not html:
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
else:
# https://stackoverflow.com/questions/882712/sending-html-email-using-python#882770
msg = MIMEMultipart('alternative')
msg['Subject'] = SUBJECT
msg['From'] = FROM
msg['To'] = ", ".join(TO)
# Record the MIME types of both parts - text/plain and text/html.
# utf-8 -> https://stackoverflow.com/questions/5910104/python-how-to-send-utf-8-e-mail#5910530
part1 = MIMEText(TEXT, 'plain', "utf-8")
part2 = MIMEText(HTML, 'html', "utf-8")
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
message = msg.as_string()
try:
if port not in PORT_LIST:
raise Exception("Port %s not one of %s" % (port, PORT_LIST))
if port in (465,):
server = smtplib.SMTP_SSL(host, port)
else:
server = smtplib.SMTP(host, port)
# optional
server.ehlo()
if port in (587,):
server.starttls()
server.login(user, pwd)
server.sendmail(FROM, TO, message)
server.close()
# logger.info("SENT_EMAIL to %s: %s" % (recipients, subject))
except Exception, ex:
return ex
return None
如果仅传递body，则将发送纯文本邮件，但是，如果将html参数与body参数一起传递，则将发送html电子邮件（回退到文本内容对于不支持html / mime类型的电子邮件客户端。
用法示例：
ex = send_email(
host = 'smtp.gmail.com'
#, port = 465 # OK
, port = 587 #OK
, user = "xxx@gmail.com"
, pwd = "xxx"
, from_ = 'xxx@gmail.com'
, recipients = ['yyy@gmail.com']
, subject = "Test from python"
, body = "Test from python - body"
)
if ex:
print("Mail sending failed: %s" % ex)
else:
print("OK - mail sent"
顺便说一句。如果您想将gmail用作测试或生产SMTP服务器， 启用对不那么安全的应用程序的临时或永久访问：