Question

我有一组类以这种方式在angular之外接收一些依赖。

import {TypeATest} from '...../TypeA.model'
import { TypeBTest } from '..../TypeB.model'
import { SomeDependency } from './services/SomeDependency'
import { SomeAnother } from './services/SomeAnother'
  // ....

@Injectable({
  providedIn: 'root'
})
export class TestingService {
  this.activeTest: AnyTestType;

  constructor(private readonly injectorService: InjectorService) {}

  loadTest(TypeOfTest) {
    const someDependency = this.injectorService.get(SomeDependency)
    const someAnother = this.injectorService.get(SomeAnother)
      switch(TypeOfTest) {
        case TypeA:
            injector
            this.activeTest = new TypeATest(someDependency, someAnother);
            break;
        case TypeB:
            this.activeTest = new TypeBTest(someAnother);
            break;
      }
  }

  startTest(){
    this.activeTest.start()
  }

// .. more this.activeTest uses...
}

我正在对加载该外部类的服务进行单元测试，但是我不想创建TypeATest，TypeBTest或类似内容，但只是模拟结果（它们都具有相同的API），但是我是找不到如何嘲笑他们。有办法吗？

Answer 1

这两个构造函数的名称分别为各自模块的出口。

您可以在模块工厂中使用jest.mock来模拟整个模块：

jest.mock('...../TypeA.model', () => { const start = jest.fn(); const result = { start }; return jest.fn(() => result); }); test('something', () => { // ... });

...或使用jest.spyOn仅模拟模块的命名导出：

import * as TypeB from '..../TypeB.model'; test('something', () => { const spy = jest.spyOn(TypeB, 'TypeBTest'); const start = jest.fn(); spy.mockReturnValue({ start }); // ... })

用茉莉花，笑话或ts-mockito模拟类的构造函数

1 个答案: