Haskell：如何将元素列表拆分为几个列表[a]-> [[a]]

Question

我有一个给定的Int（例如3）和一个元素列表。

我想将这些元素按3个列表排序（取决于给定的int）。

例如：3 [a,b,c,d,e,f,g] -> [[a,d,g],[b,e],[c,f]]

我只知道函数：

chunksOf 3 ['a'..'z']
["abc","def","ghi","jkl","mno","pqr","stu","vwx","yz"]

提前谢谢

Answer 1

您要transpose：

transpose ["abc", "def", "g"]

给予

["adg","be","cf"]

您可以将其组合

transpose $ chunksOf 3 "abcdefg"