Question

 @Query("SELECT count(*) as count FROM #{#n1ql.bucket} WHERE #{#n1ql.filter} ")
 long myCount();

我当前的数据框结果

import pandas as pd
import os

list_of_dict2 = [[{'1580674': ['HA-567034786', 'AB-1018724']}], [{'1554970': ['AB-6348403', 'HA-7298656']}, {'1554970': ['AB-2060953', 'HA-990228']}, {'1554970': ['HA-7287204', 'AB-1092380','GR-33333']}]]

list_of_dict = []
for i in list_of_dict2:
   for j in i:
     list_of_dict.append(list(j.values())[0])

df = pd.DataFrame(list_of_dict)
print(df)

使用字典列表，我可以使用下面的代码生成数据框。但是我的问题是我有一些使其很多词典列表出现问题。让我解释一下我想要实现的目标。

例如，对于数据帧的每一行，我想使它成为多对多字典，并且在列表上具有多个值。说，最后一个索引3 我要像下面这样

预期输出：（用于第二个索引）

              0           1         2
0  HA-567034786  AB-1018724      None
1    AB-6348403  HA-7298656      None
2    AB-2060953   HA-990228      None
3    HA-7287204  AB-1092380  GR-33333

预期输出：（用于第三个索引）

{ 

    "AB-2060953" : ['HA-990228'],
    "HA-990228" : ['AB-2060953']

}

Answer 1

一种方法可能是：

import 'package:flutter/material.dart';

void main() {
  runApp(MyTabs());
}

class MyTabs extends StatefulWidget {
  @override
  MyTabsState createState() => MyTabsState();
}

class MyTabsState extends State<MyTabs> with SingleTickerProviderStateMixin {
  TabController controller;
  Color currentTabColor;

  @override
  void initState() {
    super.initState();
    currentTabColor = Colors.red;
    controller = TabController(vsync: this, length: 3);
  }

  @override
  void dispose() {
    controller.dispose();
    super.dispose();
  }

  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      theme: ThemeData(
        primaryColor: currentTabColor,
      ),
      home: Scaffold(
        appBar: AppBar(
          title: Text('Multi Colored Tab Bar'),
          bottom: TabBar(
            onTap: (tabIndex) {
              if (tabIndex == 0)
                currentTabColor = Colors.red;
              else if (tabIndex == 1)
                currentTabColor = Colors.blue;
              else
                currentTabColor = Colors.green;
              setState(() {
                currentTabColor = currentTabColor;
              });
            },
            controller: controller,
            tabs: <Tab>[
              Tab(
                text: 'First Tab',
              ),
              Tab(text: 'Second Tab'),
              Tab(text: 'Third Tab'),
            ],
          ),
        ),
        body: TabBarView(
          controller: controller,
          children: <Widget>[
            Scaffold(backgroundColor: Colors.red),
            Scaffold(backgroundColor: Colors.blue),
            Scaffold(backgroundColor: Colors.green),
          ],
        ),
      ),
    );
  }
}

或者，在不假设唯一性且不处理集合的情况下，

def make_dict(row):
    s = set(row[~row.isna()])
    return {x: list(s - {x}) for x in s}

df.apply(make_dict, axis=1)

# Output:
0    {'AB-1018724': ['HA-567034786'], 'HA-567034786': ['AB-1018724']}
1    {'AB-6348403': ['HA-7298656'], 'HA-7298656': ['AB-6348403']}
2    {'HA-990228': ['AB-2060953'], 'AB-2060953': ['HA-990228']}
3    {'GR-33333': ['AB-1092380', 'HA-7287204'], 'AB-1092380': ['GR-33333', 'HA-7287204'], 'HA-7287204': ['GR-33333', 'AB-1092380']}
dtype: object

从python数据帧生成多对多字典关系列表

1 个答案: