XSLT-1.0建立一对一关系

时间：2019-03-26 20:50:10

标签： xml xslt xslt-1.0

我生成了一个报告，该报告以一对多的方式显示记录。但是，我需要将它们显示为一个。我使用XSLT转换了源XML，但是没有用。

我开发了此XSLT来转换XML。
但是，它不起作用。

这是我的XML：

<?xml version="1.0" encoding="utf-16"?>
<Records count="2">
    <Record contentId="1442264" levelId="98" levelGuid="b085b230-e20f-41df- 
a849-f5d6811447ea" moduleId="167" parentId="0">
        <Record contentId="1608202" levelId="155" levelGuid="20b8e343-96c0-4aed- 
804c-7e40b489f31b" moduleId="537" parentId="0">
            <Field id="17169" guid="ed20bfb9-d2e9-44c2-9b22-5e39d26beae4" 
type="6">16913</Field>
            <Field id="27556" guid="d378d42e-42da-4a23-906a-722fcb7d761e" 
type="6">1608202</Field>
        </Record>
        <Record contentId="1608204" levelId="155" levelGuid="20b8e343-96c0-4aed- 
804c-7e40b489f31b" moduleId="537" parentId="0">
            <Field id="17169" guid="ed20bfb9-d2e9-44c2-9b22-5e39d26beae4" 
type="6">16915</Field>
            <Field id="27556" guid="d378d42e-42da-4a23-906a-722fcb7d761e" 
type="6">1608204</Field>
        </Record>
        <Field id="2260" guid="a69370c5-b6a7-4e20-a073-dd6bbd131e43" 
type="6">1442264</Field>
    </Record>
    <Record contentId="1445144" levelId="98" levelGuid="b085b230-e20f-41df- 
a849-f5d6811447ea" moduleId="167" parentId="0">
        <Record contentId="1608203" levelId="155" levelGuid="20b8e343-96c0-4aed- 
804c-7e40b489f31b" moduleId="537" parentId="0">
            <Field id="17169" guid="ed20bfb9-d2e9-44c2-9b22-5e39d26beae4" 
type="6">16914</Field>
            <Field id="27556" guid="d378d42e-42da-4a23-906a-722fcb7d761e" 
type="6">1608203</Field>
        </Record>
        <Record contentId="1608205" levelId="155" levelGuid="20b8e343-96c0-4aed- 
804c-7e40b489f31b" moduleId="537" parentId="0">
            <Field id="17169" guid="ed20bfb9-d2e9-44c2-9b22-5e39d26beae4" 
type="6">16916</Field>
            <Field id="27556" guid="d378d42e-42da-4a23-906a-722fcb7d761e" 
type="6">1608205</Field>
        </Record>
        <Field id="2260" guid="a69370c5-b6a7-4e20-a073-dd6bbd131e43" 
type="6">1445144</Field>
    </Record>
    <Metadata>
        <FieldDefinitions>
            <FieldDefinition id="2260" guid="a69370c5-b6a7-4e20-a073-dd6bbd131e43" 
name="Issue ID" alias="Finding_ID" />
            <FieldDefinition id="17169" guid="ed20bfb9-d2e9-44c2-9b22-5e39d26beae4" 
name="CAP ID" alias="Remediation_Plan_ID" />
            <FieldDefinition id="17182" guid="e950ebab-1bf6-4fc8-818b-88a54fd12f89" 
name="CAP Title" alias="Name" />
            <FieldDefinition id="27556" guid="d378d42e-42da-4a23-906a-722fcb7d761e" 
name="X - Tracking ID" alias="X__Tracking_ID" />
        </FieldDefinitions>
    </Metadata>
    <LevelCounts>
        <LevelCount id="98" guid="b085b230-e20f-41df-a849-f5d6811447ea" count="2" 
/>
        <LevelCount id="155" guid="20b8e343-96c0-4aed-804c-7e40b489f31b" 
count="4" />
    </LevelCounts>
</Records>

这是我的XSLT：

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns="http://www.archer-tech.com/">
    <xsl:output method="xml" indent="yes" />

    <xsl:template match="/">
        <ArcherRecords>
            <xsl:for-each select="Records/Record/Field[@guid='b085b230-e20f-41df- 
 a849-f5d6811447ea']/Reference">
                <ArcherRecord>
                    <IssueID>
                        <xsl:value-of select="."/>
                    </IssueID>
                    <CAPID>
                        <xsl:value-of select="../../Field[@guid='ed20bfb9-d2e9-44c2-9b22- 
 5e39d26beae4']"/>
                    </CAPID>
                    <XTrackingID>
                        <xsl:value-of select="../../Field[@guid='d378d42e-42da- 
 4a23-906a-722fcb7d761e']"/>
                    </XTrackingID>
                </ArcherRecord>
            </xsl:for-each>
        </ArcherRecords>
    </xsl:template>

</xsl:stylesheet>

我的输入是：

Issue ID                  CAP ID          X - Tracking ID
Issue-1442264             CAP-16913       1608202
                          CAP-16915       1608204
Issue-1445144             CAP-16914       1608203
                          CAP-16916       1608205

预期输出为：

Issue ID           CAP ID       X - Tracking ID
Issue-1442264      CAP-16913    1608202
Issue-1442264      CAP-16915    1608204
Issue-1445144      CAP-16914    1608203
Issue-1445144      CAP-16916    1608205

实际输出为：

 <?xml version="1.0" encoding="UTF-8"?>
 <ArcherRecords xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
           xmlns="http://www.archer-tech.com/"/>

2 个答案:

答案 0 :(得分：0)

XSLT失败的主要原因是XML和XSLT都有不正确的空格处理。因此，表达式不匹配！

解决方案是修复换行符！

例如：
您相关的selectedProducts = [ { id: 12, sku: 12064273040195392, title: "Cat Tee Black T-Shirt", availableSizes: ["XS", "S"], style: "Black with custom print", price: 10.9, imgUrl: photo1, currencyId: "GBP", currencyFormat: "£", isFreeShipping: true }, { id: 13, sku: 51498472915966370, title: "Dark Thug Blue-Navy T-Shirt", availableSizes: ["M"], style: "Front print and paisley print", price: 29.45, imgUrl: photo2, currencyId: "GBP", currencyFormat: "£", isFreeShipping: true }, { id: 12, sku: 12064273040195392, title: "Cat Tee Black T-Shirt", availableSizes: ["XS", "S"], style: "Black with custom print", price: 10.9, imgUrl: photo1, currencyId: "GBP", currencyFormat: "£", isFreeShipping: true } ]; 属性包含一个换行符和一些空格，这使得它（几乎）无法与连接的XPath表达式的字符串值匹配。

因此，您将不得不面对不方便的任务来更正XML的换行符。

解决断行问题后，以下XSLT-1.0代码将为您提供一些有用的输出：

levelGuid

其输出为： 

<xsl:template match="/Records">
    <ArcherRecords>
        <xsl:for-each select="Record[@levelGuid='b085b230-e20f-41df-a849-f5d6811447ea']">
            <ArcherRecord>
                <IssueID>
                    <xsl:value-of select="@contentId"/>
                </IssueID>
                <xsl:for-each select="Record">
                    <CAPID>
                        <xsl:value-of select="Field[@guid='ed20bfb9-d2e9-44c2-9b22-5e39d26beae4']"/>
                    </CAPID>
                    <XTrackingID>
                        <xsl:value-of select="Field[@guid='d378d42e-42da-4a23-906a-722fcb7d761e']"/>
                    </XTrackingID>
                </xsl:for-each>
            </ArcherRecord>
        </xsl:for-each>
    </ArcherRecords>
</xsl:template>

这是您问题的答案。
现在，剩下的任务是获取纯文本输出。
创建所需输出的模板是：

<?xml version="1.0"?>
<ArcherRecords xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:arch="http://www.archer-tech.com/">
    <ArcherRecord>
        <IssueID>1442264</IssueID>
        <CAPID>16913</CAPID>
        <XTrackingID>1608202</XTrackingID>
        <CAPID>16915</CAPID>
        <XTrackingID>1608204</XTrackingID>
    </ArcherRecord>
    <ArcherRecord>
        <IssueID>1445144</IssueID>
        <CAPID>16914</CAPID>
        <XTrackingID>1608203</XTrackingID>
        <CAPID>16916</CAPID>
        <XTrackingID>1608205</XTrackingID>
    </ArcherRecord>
</ArcherRecords>

其输出为： 

<xsl:output method="text" indent="yes" />

<xsl:template match="/Records">
    <xsl:text>Issue ID&#x9;CAP ID&#x9;&#x9;X - Tracking ID&#xa;</xsl:text>
    <xsl:for-each select="Record[@levelGuid='b085b230-e20f-41df-a849-f5d6811447ea']">
        <xsl:for-each select="Record">
            <xsl:value-of select="concat('Issue-',../@contentId)"/><xsl:text>&#x9;</xsl:text>
            <xsl:value-of select="concat('CAP-',Field[@guid='ed20bfb9-d2e9-44c2-9b22-5e39d26beae4'])"/><xsl:text>&#x9;</xsl:text>
            <xsl:value-of select="Field[@guid='d378d42e-42da-4a23-906a-722fcb7d761e']"/>
            <xsl:text>&#x9;&#xa;</xsl:text>
        </xsl:for-each>
    </xsl:for-each>
</xsl:template>

答案 1 :(得分：0)

您只需要找到一对多XML关系中的image_id，然后迭代one即可生成新的XML元素。

.xsl 

many

根据您的XML得出的结果是

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    exclude-result-prefixes="msxsl" xmlns="http://www.archer-tech.com/">
    <xsl:output method="xml" indent="yes" />
    <xsl:template match="/">
        <ArcherRecords>
            <xsl:for-each select='//Record[@levelGuid="b085b230-e20f-41df-a849-f5d6811447ea"]'>
              <xsl:param name="issueid">
                    <xsl:value-of select="Field[@guid='a69370c5-b6a7-4e20-a073-dd6bbd131e43']"></xsl:value-of>
                </xsl:param>
                <xsl:for-each select="Record">
                    <ArcherRecord>
                        <IssueID>Issue-<xsl:value-of select="$issueid"></xsl:value-of>
                        </IssueID>
                        <CAPID>CAP-<xsl:value-of select="Field[@guid='ed20bfb9-d2e9-44c2-9b22-5e39d26beae4']" />
                        </CAPID>
                        <XTrackingID>
                            <xsl:value-of select="Field[@guid='d378d42e-42da-4a23-906a-722fcb7d761e']" />
                        </XTrackingID>
                    </ArcherRecord>
                </xsl:for-each>
            </xsl:for-each>
        </ArcherRecords>
    </xsl:template>
</xsl:stylesheet>

固定的换行符XML：

<ArcherRecords>
    <ArcherRecord>
        <IssueID>Issue-1442264</IssueID>
        <CAPID>CAP-16913</CAPID>
        <XTrackingID>1608202</XTrackingID>
    </ArcherRecord>
    <ArcherRecord>
        <IssueID>Issue-1442264</IssueID>
        <CAPID>CAP-16915</CAPID>
        <XTrackingID>1608204</XTrackingID>
    </ArcherRecord>
    <ArcherRecord>
        <IssueID>Issue-1445144</IssueID>
        <CAPID>CAP-16914</CAPID>
        <XTrackingID>1608203</XTrackingID>
    </ArcherRecord>
    <ArcherRecord>
        <IssueID>Issue-1445144</IssueID>
        <CAPID>CAP-16916</CAPID>
        <XTrackingID>1608205</XTrackingID>
    </ArcherRecord>
</ArcherRecords>
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