我一直在用纯Python编写一个跟踪跟踪器,只是为了好玩,而且由于我以前的着色不太漂亮(Lambert's cosine law),我正在尝试实现递归路径跟踪。
我的引擎输出中止:
我的路径追踪功能是递归定义的,如下所示:
def TracePath2(ray, scene, bounce_count):
result = 100000.0
hit = False
answer = Color(0.0, 0.0, 0.0)
for object in scene.objects:
test = object.intersection(ray)
if test and test < result:
result = test
hit = object
if not hit:
return answer
if hit.emittance:
return hit.diffuse * hit.emittance
if hit.diffuse:
direction = RandomDirectionInHemisphere(hit.normal(ray.position(result)))
n = Ray(ray.position(result), direction)
dp = direction.dot(hit.normal(ray.position(result)))
answer += TracePath2(n, scene, bounce_count + 1) * hit.diffuse * dp
return answer
我的场景(我制作了自定义的XML描述格式)是这样的:
<?xml version="1.0" ?>
<scene>
<camera name="camera">
<position x="0" y="-5" z="0" />
<direction x="0" y="1" z="0" />
<focalplane width="0.5" height="0.5" offset="1.0" pixeldensity="1600" />
</camera>
<objects>
<sphere name="sphere1" radius="1.0">
<material emittance="0.9" reflectance="0">
<diffuse r="0.5" g="0.5" b="0.5" />
</material>
<position x="1" y="0" z="0" />
</sphere>
<sphere name="sphere2" radius="1.0">
<material emittance="0.0" reflectance="0">
<diffuse r="0.8" g="0.5" b="0.5" />
</material>
<position x="-1" y="0" z="0" />
</sphere>
</objects>
</scene>
我很确定我的引擎存在一些根本性缺陷,但我找不到它......
这是我的新追踪功能:
def Trace(ray, scene, n):
if n > 10: # Max raydepth of 10. In my scene, the max should be around 4, since there are only a few objects to bounce off, but I agree, there should be a cap.
return Color(0.0, 0.0, 0.0)
result = 1000000.0 # It's close to infinity...
hit = False
for object in scene.objects:
test = object.intersection(ray)
if test and test < result:
result = test
hit = object
if not hit:
return Color(0.0, 0.0, 0.0)
point = ray.position(result)
normal = hit.normal(point)
direction = RandomNormalInHemisphere(normal) # I won't post that code, but rest assured, it *does* work.
if direction.dot(ray.direction) > 0.0:
point = ray.origin + ray.direction * (result + 0.0000001) # We're going inside an object (for use when tracing glass), so move a tad bit inside to prevent floating-point errors.
else:
point = ray.origin + ray.direction * (result - 0.0000001) # We're bouncing off. Move away from surface a little bit for same reason.
newray = Ray(point, direction)
return Trace(newray, scene, n + 1) * hit.diffuse + Color(hit.emittance, hit.emittance, hit.emittance) # Haven't implemented colored lights, so it's a shade of gray for now.
我很确定路径追踪代码可以正常运行,因为我手动投射了一些光线并获得了非常合理的结果。我现在遇到的问题是相机不会通过所有像素平面中的像素拍摄光线。我制作了这段代码来查找与像素相交的光线,但它无法正常工作:
origin = scene.camera.pos # + 0.5 because it #
# puts the ray in the # This calculates the width of one "unit"
# *middle* of the pixel #
worldX = scene.camera.focalplane.width - (x + 0.5) * (2 * scene.camera.focalplane.width / scene.camera.focalplane.canvasWidth)
worldY = scene.camera.pos.y - scene.camera.focalplane.offset # Offset of the imaging plane is know, and it's normal to the camera's direction (directly along the Y-axis in this case).
worldZ = scene.camera.focalplane.height - (y + 0.5) * (2 * scene.camera.focalplane.height / scene.camera.focalplane.canvasHeight)
ray = Ray(origin, (scene.camera.pos + Point(worldX, worldY, worldZ)).norm())
答案 0 :(得分:4)
我的第一个问题是if test > result:
应if test < result:
吗?你正在寻找最接近的命中,而不是最远的命中。
其次,为什么要将direction*0.00001
添加到此处n = Ray(ray.position(result) + direction * 0.00001, direction)
的生命值?这会让你的新光线开始在球体内。我相信当你递归调用TracePath2
时,你乘以的点积将是负数,这有助于解释问题。
编辑:更新的问题
这一行令我困惑:answer += TracePath2(n, scene, bounce_count + 1) * hit.diffuse * dp
。首先answer
只是Color(0.0, 0.0, 0.0)
所以你可以简单地return racePath2(n, scene, bounce_count + 1) * hit.diffuse * dp
。但这仍然困扰着我,因为我不明白为什么你要递归调用和hit.diffuse
。这样的事情对我来说更有意义return racePath2(n, scene, bounce_count + 1) * dp + hit.diffuse
。还有一件事,你永远不会检查bounce_count
。无论如何,你永远不会永远地在这个场景中进行渲染,但是如果你想渲染更大的场景,你会在开始时想要这样的东西if bounce_count > 15: return black
。
编辑2:
我看到的一件事,我仍然想知道的是if-else到底是什么。首先,我不完全确定代码的这一部分是做什么的。我想你正在测试光线是否在物体内部。在这种情况下,您的测试就像这样inside = normal.dot(ray.direction) > 0.0
。我只是针对normal
而不是direction
进行测试,因为在半球中使用随机方向可能会给出错误的答案。现在,如果你在想要离开的物体内,但是如果你已经出去,你想留在外面吗?就像我说的那样,我不太清楚应该做什么。