我正在研究一些应该实现众所周知的Java代码 使用循环链表的约瑟夫斯问题。以下是关于约瑟夫斯的一些信息 问题：http://en.wikipedia.org/wiki/Josephus_problem
我有一个Student class和Driver课程，我已经给我创建了我的Josephus课程。
这是学生班：http://pastebin.com/4YgSA7CM
以下是Driver类：http://pastebin.com/Nb08Dtqk
这两个类都不能修改。
我必须从头开始创建一个使用循环链接列表的Josephus类，它有效地使用了Josephus问题。
这是我完成的Josephus类，没有编译器错误：
/** Implementation of Josephus problem. The Josephus problem
is named after the historian Flavius Josephus. For more
information on this problem visit:
http://en.wikipedia.org/wiki/Josephus_problem
*/
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.ArrayList;
public class Josephus <E> {
private Node<E> head;
private int count; // number of elements in the list
/** Constructs an empty Josephus circle */
// Complexity O(1)
public Josephus() {
head = null;
count = 0;
}
/** Constructs an Josephus circle by adding the
elements from an arraylist
@param array The ArrayList of items of type E
*/
// Complexity: O(n)
public Josephus(ArrayList<E> array) {
head = null;
for (int i = 0; i < array.size(); i++)
add(array.get(i));
}
/** Inserts the specified element in the list at the
last position
@param dataItem the element to add
*/
// Complexity O(1)
@SuppressWarnings({ "unchecked" })
public void add(E dataItem) {
Node <E> node = new Node <E> (dataItem, null, null);
if (count == 0) // list is empty
head = node.previous= node ;
else
head.previous.next = node;
node.previous = head.previous;
head.previous = node;
count++;
}
// To be completed by the student
/** Inserts the specified element in the list at the
end. This method has the same behavior as add(E)
@param dataItem the element to add at the end
*/
// Complexity O(1)
public void addLast(E dataItem) {
add(dataItem);
}
/** Inserts the element at the beginning of the list
@param dataItem The element to be added
*/
// Complexity O(1)
public void addFirst(E dataItem) {
Node<E> node = new Node <E>(dataItem, null, null);
// To be completed by the student
if (head == null) // list is empty
head = head.previous = node;
else {
node.next = head;
head.previous = node;
head = node;
}
count++;
}
/** removes the element from the beginning of the list
@return The element that was remvoed
@throws NoSuchElementException if the list is empty
*/
// Complexity O(1)
public E removeFirst() {
// To be completed by the student
if (head != null) {
E item = head.data;
if (head == head.previous) // list has only one element
head = head.previous = null;
else { // list has more than 1 element
head = head.next;
head.previous = null;
}
count--;
return item;
}
else throw new NoSuchElementException();
}
/** removes the element from the end of the list
@return The element that was remvoed
@throws NoSuchElementException if the list is empty
*/
// Complexity O(1)
public E removeLast() {
// to be completed by the student
if (head.previous != null) {
E item = head.previous.data;
if (head == head.previous) // list has only one item
head = head.previous = null;
else { // list has more than one element
head.previous = (head.previous).previous;
head.previous.next = null;
}
count--;
return item;
}
else throw new NoSuchElementException();
}
/** returns a reference to the element at
position index
@param index The index of the element being sought
@return A reference to the element at position index
@throws IndexOutOfBoundsException if index is out of range
*/
// Complexity O(n)
public E get(int index) {
if ((index < 0) || (index >= count))
throw new IndexOutOfBoundsException(Integer.toString(index));
Node<E> temp = head;
for (int i = 0; i < index; i++)
temp = temp.next;
return temp.data;
}
/** Sets the element at position index to reference
anEntry.
@param index The position of the element that is to
be set
@param anEntry The new value at position index
@return the element that was previously at position index
@throws IndexOutOfBoundsException if index is out of range
*/
// Complexity O(n)
public E set(int index, E anEntry) {
if ((index < 0) || (index >= count))
throw new IndexOutOfBoundsException(Integer.toString(index));
Node<E> temp = head;
for (int i = 0; i < index; i++)
temp = temp.next;
E result = temp.data;
temp.data = anEntry;
return result;
}
/** Inserts the specified element in the list at a
given index
@param index The position at which the new element
has to be inserted
@param anEntry The element to add
@throws IndexOutOfBoundsException if index is out of range
*/
// Complexity O(n)
public void add(int index, E anEntry) {
// To be completed by the student
if ((index < 0) || (index > count))
throw new IndexOutOfBoundsException(Integer.toString(index));
if (index == 0) addFirst(anEntry);
else if (index == count) addLast(anEntry);
else {
Node <E> node = head;
int i = 0;
while(node!=null && i<index){
i++;
node = node.next;
}
Node<E> newNode = new Node <E> (anEntry, node, node.next);
node.next.previous = newNode;
node.next = newNode;
count++;
}
}
/** searches for target and returns the position of the
first occurrence, or -1 if it is not in the list
@param target The element we are searching for
@return The position of target if found; -1 if not found
*/
// Complexity O(n)
public int indexOf(E target) {
Node<E> temp = head;
for (int i = 0; i < count; i++) {
if (temp.data.equals(target)) return i;
temp = temp.next;
}
return -1;
}
/** removes the element at position index
@param index The index of the element to be removed
@return The element that was removed
@throws IndexOutOfBoundsException if index is invalid
*/
// Complexity O(n)
public E remove(int index) {
// to be completed by the student
if ((index < 0) || (index >= count))
throw new IndexOutOfBoundsException(Integer.toString(index));
Node<E> temp = head;
for(int i =0;i<index; i++)
temp = temp.next;
E result = temp.data;
temp.next = temp.previous;
return result;
}
/** sets the start position for the Josephus game
@param index The starting position
@throws IndexOutOfBoundsException if index is invalid
*/
// Complexity O(n)
public void setStartPosition(int index) {
if ((index < 0) || (index >= count))
throw new IndexOutOfBoundsException(Integer.toString(index));
for (int i = 0; i < index; i++)
head = head.next;
}
/* This private utility method is used in startJosephus
method.
Complexity O(1)
*/
private void removeAfter(Node<E> node) {
node.next = node.next.next;
node.next.previous = node;
count--;
}
/** simulates the Josephus game by killing every other person
until the winner is the only one left.
@return The survivor of the game
*/
public E startJosephus() {
E item =head.data;
if(head.next != null){
if(head == head.previous)
return item;
else
while(count>1);
removeAfter(head);
head =head.next;
}
return item;
}
/** Returns a list-iterator of the elements in this list
(in proper sequence), starting at the beginning
of the list.
*/
public ListIterator <E> iterator() {
return new myIterator();
}
/** @return The number of elements in the list
*/
public int size() {
return count;
}
// this is an inner clss implementing the ListIterator
// interface.
// visit http://docs.oracle.com/javase/1.4.2/docs/api/java/util/ListIterator.html
// for a complete list of methods in ListIterator
private class myIterator implements ListIterator <E> {
private Node<E> forward = head;
private Node<E> backward = head;
private boolean firstTime = true;
/** checks if a current item E is the last
in the collection
*/
public boolean hasNext() {
return (forward != null);
}
/** returns the next item in the collection if
there is one. If there is no more items
throws NoSuchElementException
*/
public E next() {
if (forward == null) throw
new NoSuchElementException();
else {
E item = forward.data;
forward = forward.next;
if (forward == head) forward = null;
return item;
}
}
/** checks if a current item is the first
in the collection
*/
public boolean hasPrevious() {
return (backward != null);
}
/** returns the previous item in the collection if
there is one. If there is no more items
throws NoSuchElementException
*/
public E previous() {
if (backward == null) throw
new NoSuchElementException();
else {
if (firstTime) {
backward = backward.previous;
firstTime = false;
}
E item = backward.data;
backward = backward.previous;
if (backward == head.previous) backward = null;
return item;
}
}
/* this operation is not supported */
public void add(E obj) {
throw new UnsupportedOperationException();
}
/* this operation is not supported */
public void set(E obj) {
throw new UnsupportedOperationException();
}
/* this operation is not supported */
public int previousIndex() {
throw new UnsupportedOperationException();
}
/* this operation is not supported */
public int nextIndex() {
throw new UnsupportedOperationException();
}
/* this operation is not supported */
public void remove() {
throw new UnsupportedOperationException();
}
}
private static class Node <E> {
private E data;
private Node<E> next;
private Node<E> previous;
/** constructor Creates an empty node with both next and
previous fields set to be null
@param dataItem - item to be inserted
*/
private Node(E dataItem) {
data= dataItem;
previous = next = null;
}
/** creates a new node that references another node
@param dataItem The data stored
@param previousNodeRef The node previous to this node
@param nextNodeRef The node next to this node
*/
private Node(E dataItem, Node<E> previousNodeRef, Node <E> nextNodeRef ) {
data = dataItem;
previous = previousNodeRef;
next = nextNodeRef;
}
}
}
我的startJosephus方法是我认为的主要问题。虽然不完全确定。这是上面代码中的startJosephus方法：
/** simulates the Josephus game by killing every other person
until the winner is the only one left.
@return The survivor of the game
*/
public E startJosephus() {
E item =head.data;
if(head.next != null){
if(head == head.previous)
return item;
else
while(count>1);
removeAfter(head);
head =head.next;
}
return item;
}
以下是我运行Josephus课程时正在运行的内容：http://pastebin.com/5GnChgYd
以下是输出应该产生的内容：http://pastebin.com/Qr5dCZJp
此外，以下是用于生成此输出的两个输入文件：
StudentList1.txt：http://pastebin.com/ysjevQ8u
StudentList2.txt：http://pastebin.com/r2YeppNm
根据我得到的输出和我应该得到的输出，似乎约瑟夫斯问题没有开始并模拟杀戮狂欢。但是，我不知道我的代码有什么问题。我的代码不能有尾巴，因为它是循环链接列表。知道我在这里做错了什么吗？对不起所有的Pastebin链接，它似乎是一种更好的方式来组织我在这里呈现的所有代码。希望能听到你的想法。
EDIT:
There are 21 persons in this list
The game starts with McElroy,Breanna at starting position
The killing spree begins......
The sole survivor at the end of this gruesome game is McElroy,Breanna
Exception in thread "main" java.lang.NullPointerException
at Josephus$Node.access$5(Josephus.java:383)
at Josephus.add(Josephus.java:49)
at Josephus.addLast(Josephus.java:66)
at Driver.main(Driver.java:96)
这是我在使用无限循环修复问题后得到的新运行时错误。有什么建议？？？？什么是所有这些空指针异常
答案 0 :(得分：2)
if(head.next != null) {
if (head == head.previous)
return item;
else
while(count>1);
removeAfter(head);
head =head.next;
这段代码将在所有情况下永远循环，除非head.next为空或head == head.previous，这在游戏开始时始终为真。因此，除了微不足道的初始条件之外，您的程序将永远循环。显然，你打算写
if(head.next != null) {
if (head == head.previous)
return item;
else
while(count>1) {
removeAfter(head);
head =head.next;
}
答案 1 :(得分：1)
我认为你有一个无限循环：
while (count > 1);