基本上我有一个Windows窗体,用户将能够绘制不同的形状(例如正方形,圆形和三角形),绘制后用户将能够突出显示这些形状中的任何一个,然后通过移动或旋转来控制突出显示的形状,我不知道如何旋转形状。任何人都可以帮忙,这是我的代码(只能画一个正方形) PS:用户需要在表单上单击两次以在这两个点之间绘制形状,如下所示,我也知道我应该使用onPaint方法,但这是任务的要求
谢谢
public Square(Point keyPt, Point oppPt) // constructor
{
this.keyPt = keyPt;
this.oppPt = oppPt;
}
// You will need a different draw method for each kind of shape. Note the square is drawn
// from first principles. All other shapes should similarly be drawn from first principles.
// Ideally no C# standard library class or method should be used to create, draw or transform a shape
// and instead should utilse user-developed code.
public void draw(Graphics g, Pen blackPen)
{
// This method draws the square by calculating the positions of the other 2 corners
double xDiff, yDiff, xMid, yMid; // range and mid points of x & y
// calculate ranges and mid points
xDiff = oppPt.X - keyPt.X;
yDiff = oppPt.Y - keyPt.Y;
xMid = (oppPt.X + keyPt.X) / 2;
yMid = (oppPt.Y + keyPt.Y) / 2;
// draw square
g.DrawLine(blackPen, (int)keyPt.X, (int)keyPt.Y, (int)(xMid + yDiff / 2), (int)(yMid - xDiff / 2));
g.DrawLine(blackPen, (int)(xMid + yDiff / 2), (int)(yMid - xDiff / 2), (int)oppPt.X, (int)oppPt.Y);
g.DrawLine(blackPen, (int)oppPt.X, (int)oppPt.Y, (int)(xMid - yDiff / 2), (int)(yMid + xDiff / 2));
g.DrawLine(blackPen, (int)(xMid - yDiff / 2), (int)(yMid + xDiff / 2), (int)keyPt.X, (int)keyPt.Y);
}
public void fillSquare(Graphics g, Brush redBrush)
{
float xDiff = oppPt.X - keyPt.X;
float yDiff = oppPt.Y - keyPt.Y;
float xMid = (oppPt.X + keyPt.X) / 2;
float yMid = (oppPt.Y + keyPt.Y) / 2;
var path = new GraphicsPath();
path.AddLines(new PointF[] {
keyPt,
new PointF(xMid + yDiff/2, yMid-xDiff/2),
oppPt
});
path.AddLines(new PointF[] {
keyPt,
new PointF(xMid - yDiff/2, yMid + xDiff/2),
oppPt
});
path.CloseFigure();
// Fill Triangle
g.FillPath(redBrush, path);
}
}
}
我尝试过这种方法,但是缺少一些东西,我不知道它是什么
private void itemRotation(PaintEventArgs e)
{
Pen blackpen = new Pen(Color.Black);
Graphics g = e.Graphics;
Font myFont = new System.Drawing.Font("Helvetica", 9);
Brush blackwriter = new SolidBrush(System.Drawing.Color.Black);
if (rotateItem)
{
for (int i = 0; i < shapes.Count; i++)
{
if (shapes[i].Selected)
{
if (shapes[i].ShapeType == (int)ShapeTypes.Square)
{
PointF center = new PointF(shapes[i].keyPt.X + (shapes[i].oppPt.X / 2.0F), shapes[i].keyPt.Y + (shapes[i].oppPt.Y / 2.0F));
shapes[i].keyPt = new Point(shapes[i].keyPt.X, shapes[i].keyPt.Y);
shapes[i].oppPt = new Point(shapes[i].oppPt.X, shapes[i].oppPt.Y);
Matrix myMatrix = new Matrix();
myMatrix.Rotate(30);
g.Transform = myMatrix;
((Square)shapes[i]).draw(g, blackpen);
g.DrawString("2nd pos", myFont, blackwriter, shapes[i].keyPt.X, shapes[i].oppPt.X);
}
}
}
}
}
答案 0 :(得分:2)
下面是如何将相同形状(GraphicsPath
)绘制到各种位置和旋转的示例。
此处的关键是以下两个命令
e.Graphics.TranslateTransform(x, y);
e.Graphics.RotateTransform(-angle);
查看以下结果:
以及用于生成它的代码:
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
// This code defines a graphics shape using a GraphicsPath
// and draws multiple copies along a grid and with various
// rotation angle angles.
e.Graphics.SmoothingMode=SmoothingMode.AntiAlias;
var target = sender as PictureBox;
// Step 1 - Define a rectangle 20 by 12 pixels, center at origin.
var gp = new GraphicsPath();
gp.AddLines(new PointF[] {
new PointF(-10, -6),
new PointF( 10, -6),
new PointF( 10, 6),
new PointF(-10, 6) });
gp.CloseFigure();
// Step 2 - Define a 10×9 grid with two loops
float angle = 0;
for (int i = 0; i<9; i++)
{
// divide the control height into 10 divisions
float y = (i+1)*target.Height/10;
for (int j = 0; j<10; j++)
{
// divide the control width into 11 divisions
float x = (j+1)*target.Width/11;
// Save the default transformation state
var state = e.Graphics.Save();
// Traslate the origin to (x,y), each grid point
e.Graphics.TranslateTransform(x, y);
// Rotate shape by an angle (negative = CCW)
e.Graphics.RotateTransform(-angle);
// Draw the shape
e.Graphics.FillPath(Brushes.LightSeaGreen, gp);
e.Graphics.DrawPath(Pens.Black, gp);
// Restore the default transformation state
e.Graphics.Restore(state);
// Increment the angle by one degree.
// The idea is to show all 90 degrees of rotation in a 10×9 grid.
angle++;
}
}
}