Question

我需要将以下内容导出到csv或excel文件中

-Distribution Group (PrimarySmtpAddress)
-Distribution Group members and each primarysmtpaddress

我尝试添加

Group email: $($group) | PrimarySmtpAddress

在下面的代码中，但没有添加。

#This is what works but is missing
$groups = Get-DistributionGroup -ResultSize Unlimited | Select -ExpandProperty name

ForEach ($group in $groups) 
{
"Group Name: $($group)`nGroup Members:`n"

Get-DistributionGroupMember $group |ft name,alias,primarysmtpaddress 

}

我缺少通讯组的主要smtp地址吗？

Answer 1

正如Lee_Daily所评论的那样，您通过执行Name除去了Select -ExpandProperty name以外的所有属性。接下来，如果要导出到CSV文件，请不要使用Format-Table（ft），因为那只是将结果格式化到控制台。

您应该做的是创建一个对象数组，并将其传递到Export-Csv cmdlet，如下面的（未经测试的）代码所示：

$outputFile = '<PATH AND FILENAME FOR THE EXPORTED CSV FILE>'

Get-DistributionGroup -ResultSize Unlimited | ForEach-Object {
    # The Identity parameter for Get-DistributionGroupMember specifies the distribution group
    # or mail-enabled security group. You can use any value that uniquely identifies the group.
    # The cmdlet also accepts the Identity parameter as pipeline input, so 
    # $_ | Get-DistributionGroupMember will also work.
    $Members = Get-DistributionGroupMember -Identity $($_.PrimarySmtpAddress) 
    foreach ($member in $Members) { 
        [PSCustomObject]@{
            GroupName   = $_.DisplayName
            GroupAlias  = $_.Alias
            GroupEmail  = $_.PrimarySMTPAddress
            MemberName  = $member.DisplayName
            MemberEmail = $member.PrimarySMTPAddress
            # Maybe also add RecipientType to distinguish between users and groups?
            # MemberType  = $member.RecipientType
        }
    } 
} | Export-Csv -Path $outputFile -NoTypeInformation

希望有帮助

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