Question

我制作了一个运行ping并在文本字段中显示结果的应用程序。当我单击开始ping按钮时，GUI挂起，并且没有任何输出到文本字段。可以理解为什么该GUI挂起，GUI正在等待控制台应用程序完成。我不明白该如何在控制台应用程序的文本字段中实现输出。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Diagnostics;

namespace WindowsFormsApp4
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            Class1 ping = new Class1();
            ping.startPing();
            string output = ping.output();
            richTextBox1.AppendText(output + "\n");
            richTextBox1.Update();
        }

        static private void richTextBox1_TextChanged(object sender, EventArgs e)
        {

        }
    }

    class Class1
    {
        private Process p = new Process();

        public void startPing()
        {
            p.StartInfo.UseShellExecute = false;
            p.StartInfo.CreateNoWindow = true;
            p.StartInfo.RedirectStandardOutput = true;
            p.StartInfo.FileName = "c:/windows/system32/ping";
            p.StartInfo.Arguments = "8.8.8.8 -t";
            p.Start();
        }

        public string output()
        {
            string output = p.StandardOutput.ReadToEnd();
            p.WaitForExit();
            return output;
        }
    }
}

Answer 1

此代码将有助于解决您的查询。

  private void button1_Click(object sender, EventArgs e)
  {
          var worker = new BackgroundWorker();
          worker.DoWork += (o, ea) =>
          {
                Class1 ping = new Class1();
                ping.startPing();
                string output = ping.output();
                richTextBox1.AppendText(output + "\n");
                richTextBox1.Update();

          };
          worker.RunWorkerCompleted += (o, ea) =>
          {
                //You will get pointer when this worker finished the job.
          };
          worker.RunWorkerAsync();
    }

让我知道在用源实现它之后是否有任何问题。

启动控制台应用程序后，c＃GUI冻结

1 个答案: