Question

我已经编写了一个C程序，可以模拟用户输入的X年的彩票过程，一旦输入了年数，它将模拟很多年的每周抽奖。如果预先输入的数字（已经在代码中）匹配，程序还需要打印出该数字，并且还需要打印出与数字匹配的次数，例如

6个匹配的数字（）
5个匹配的数字（）
等

这是我到目前为止所拥有的代码，所有内容均已编译并运行良好：

#include <stdio.h>

int main(int argc, char const *argv[])
{
    //Welcome the User to the Program
    puts("============================");
    puts("       WELCOME TO       ");
    puts("============================");
    puts("  PROJECT : JACKPOT DREAMS  ");
    puts("============================");

    //Rogers 6 Original Numbers
    int nums[6] = { 5, 11, 15, 33, 42, 43 };

    //Ask how many years to simulate
    int years = 0;
    printf("How many years would you like to sleep for? :\n");
    scanf("%d", &years);
    printf("Ok. I will now play the lottery %d year(s)\n",years);
    printf("Sleep Tight :)....\n");

    //Generate Random Numbers
    int ctr;
    int randnums[6];
    srand(time(NULL));
    while (years-- > 0) {
        for( ctr = 0; ctr < 6; ctr++ ) randnums[ctr] = (rand() % 50);

        //Check Numbers with Rogerns numbers
        int win = 1;
        for( ctr = 0; ctr < 6; ctr++ )
        {
            if(randnums[ctr] != nums[ctr])
            {
                win = 0;
                break; // if there's a mismatch we don't need to continue
            }
        }


        return 0;
    }

}

有人知道我会怎么做吗？

Answer 1

首先，您似乎在循环学习第一年后return。您应该将return语句移到大括号之外。其次，如一些评论所述，您应该更加仔细地编写块，并做出正确的缩进。

下面，我重写了您的程序，以打印出给定年份中是否有某些数字匹配。如果所有数字都匹配，则为“获胜者！”也被打印。为此，我添加了一些变量和print语句。

希望这会有所帮助。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int
main(int argc, char const *argv[])
{
    //Welcome the User to the Program
    puts("============================");
    puts("         WELCOME TO         ");
    puts("============================");
    puts("  PROJECT : JACKPOT DREAMS  ");
    puts("============================");

    //Rogers 6 Original Numbers
    int nums[6] = { 5, 11, 15, 33, 42, 43 };

    //Ask how many years to simulate
    int years = 0;
    printf("How many years would you like to sleep for? :\n");
    scanf("%d", &years);
    printf("Ok. I will now play the lottery %d year(s)\n",years);
    printf("Sleep Tight :)....\n");

    //Generate Random Numbers
    int numberOfWins = 0;
    int ctr;
    int randnums[6];
    srand(time(NULL));

    int currYear = 0;
    while (years-- > 0) 
    {
        currYear++;
        for( ctr = 0; ctr < 6; ctr++ ) randnums[ctr] = (rand() % 50);

        //Check Numbers with Rogerns numbers
        int win = 1, matched = 0;
        for( ctr = 0; ctr < 6; ctr++ )
        {
            if(randnums[ctr] != nums[ctr])
            {
                win = 0;
            } else {
                matched++;
            }
        }
        numberOfWins += win;

        //If any numbers matched or win, print it.
        if (matched > 0) printf("In year: %d, %d number(s) matched\n", currYear, matched);
        if (win) printf("Winner!\n");
    }

    printf("You won %d time(s)\n", numberOfWins);
    return 0;
}

如何？ -彩票模拟（C）

1 个答案: