我是C#的新手,我们有一个活动来创建彩票游戏。
1个匹配的号码赢得了$ 10 2个匹配的号码赢得$ 100 3个匹配的号码不可用$ 1,000 3个匹配的号码依次赢得10,000美元
我的代码有问题,即使有2个匹配项或3个匹配数字始终显示$ 10。任何帮助将不胜感激。
下面是源代码。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace LotteryGame
{
class Program
{
static void Main(string[] args)
{
// Matching numbers awards
int rNumMatchOne = 10;
int rNumMatchTwo = 100;
int rNumMatchThree = 1000;
int rNumMatchFour = 10000;
// Generate random numbers
Random randomNum = new Random();
// Integers Declaration
int rNum1;
int rNum2;
int rNum3;
int rNumIput;
int guessNum;
// Arrays Declartion
int[] guessNumMatch = new int[3];
int[] guessNumSort = new int[3];
int[] guessInput = new int[3];
// Restrict inputs between 1 and 4 only
rNum1 = randomNum.Next(1, 5);
rNum2 = randomNum.Next(1, 5);
rNum3 = randomNum.Next(1, 5);
Console.Write("C# Lottery Game\n\n");
Array.Sort(guessNumSort); // sort random numbers
// Guess number input loop
for (rNumIput = 0; rNumIput < 3; rNumIput++)
{
Console.Write("Guess Number " + (rNumIput + 1) + ": ");
guessNum = Convert.ToInt32(Console.ReadLine());
// Invalid input between 1 and 4 program will loop back and enter correct number
while (guessNum < 1 || guessNum > 4)
{
Console.WriteLine("\n");
Console.WriteLine("Invalid Number. Please enter number between 1 and 4. \n");
Console.Write("Guess Number " + (rNumIput + 1) + ": ");
guessNum = Convert.ToInt32(Console.ReadLine());
}
guessNumMatch[rNumIput] = guessNum;
guessNumSort[rNumIput] = guessNum;
}
Array.Sort(guessNumSort);
// Display random numbers and entered numbers
Console.WriteLine();
Console.WriteLine("Generated random numbers are : " + rNum1 + " | " + rNum2 + " | " + rNum3);
Console.WriteLine("Numbers you entered are : " + guessNumMatch[0] + " | " + guessNumMatch[1] + " | " + guessNumMatch[2]);
// Matching 1 number
if (guessNumMatch[0] == rNum1 || guessNumMatch[1] == rNum2 || guessNumMatch[2] == rNum3)
{
Console.WriteLine("\n");
Console.WriteLine("CONGRATULATIONS! YOU WON: $" + rNumMatchOne);
}
// Matching 2 numbers
else if ((guessNumMatch[0] == rNum1 && guessNumMatch[1] == rNum2) || (guessNumMatch[1] == rNum2 && guessNumMatch[2] == rNum3))
{
Console.WriteLine("\n");
Console.WriteLine("CONGRATULATIONS! YOU WON: $" + rNumMatchTwo);
}
// Matching 3 numbers not in order
else if (guessNumSort[0] == guessInput[0] && guessNumSort[1] == guessInput[1] && guessNumSort[2] == guessInput[2])
{
Console.WriteLine("\n");
Console.WriteLine("CONGRATULATIONS! YOU WON: $" + rNumMatchThree);
}
// Matching 3 numbers exact order
else if (guessNumMatch[0] == rNum1 && guessNumMatch[1] == rNum2 && guessNumMatch[2] == rNum3)
{
Console.WriteLine("\n");
Console.WriteLine("CONGRATULATIONS! YOU WON: $" + rNumMatchFour);
}
else // No matching numbers
{
Console.WriteLine("\n");
Console.WriteLine("SORRY, NO MATCHING NUMBERS FOUND! ");
}
Console.WriteLine("\n");
Console.WriteLine("PRESS ANY KEY TO EXIT PROGRAM ");
Console.ReadKey();
}
}
}
答案 0 :(得分:5)
反转if语句的顺序。首先检查3个数字是否按顺序匹配,然后检查3个然后2个然后是1个,最后没有匹配。
否则,即使有多个匹配项,第一个if语句也将为true。
答案 1 :(得分:0)
如果至少其中一个数字正确,则您的第一个if
语句将评估为true。例如,如果用户正确猜出第二个和第三个数字,则guessNumMatch[1] == rNum2
将得出true
。 if(false || true || true)
的计算结果为true
,因此该语句得以执行。其他if
条语句将被跳过。
一种解决方案(就像Attersson击败我的那样)是将if语句反转-检查所有3个是否为真,然后检查2个是否为真,等等。