Question

考虑MATLAB中的以下矩阵：

01 02 03 04 05 06 07

08 09 10 11 12 13 14

15 16 17 18 19 20 21

22 23 24 25 26 27 28

29 30 31 32 33 34 35

36 37 38 39 40 41 42

43 44 45 46 47 48 49

我必须为图像的7 x 7窗口（移动）生成方向变异图。我将使用nlfilter进行处理，但是为了开发计算变量图的函数，我无法决定如何在窗口中选择元素。例如，当我考虑中心值25时，在EW方向上我只需要考虑25,26,27和28;在NE方向上，当选择的延迟为1时，我只需要考虑25,19,13和07.是否有任何标准命令可以这样做？

Answer 1

你也可以这样做：

A = eye(5);
v = A(1:size(A,1)+1:end);

导致

v = [1 1 1 1 1]

Answer 2

您可以编写一个函数来轻松获取这些元素：

A = [01 02 03 04 05 06 07
     08 09 10 11 12 13 14
     15 16 17 18 19 20 21
     22 23 24 25 26 27 28
     29 30 31 32 33 34 35
     36 37 38 39 40 41 42
     43 44 45 46 47 48 49];

c = (size(A)+1)/2;
EW = A(c(1),c(2):end)
NE = diag(A(c(1):-1:1,c(2):end))

只需将此代码写入函数（最好是m文件），执行操作并将结果传回。

diag函数返回矩阵的对角元素（或传递向量时返回对角矩阵）。

Answer 3

这是通用矩阵解决方案（不适用于MATLAB）假设矩阵AxB =

[01 AA 03 04 05 06 07
 08 09 AA 11 12 13 AA
 AA 16 17 AA 19 AA 21
 22 AA 24 25 AA 27 28
 AA 30 AA 32 33 34 35
 36 AA 38 AA 40 41 42
 43 44 AA 46 AA 48 49];

在这个矩阵中，我们希望连续3次搜索AA对角线。

解决方案： - 步骤1 对于整个矩阵，我们必须创建4个单独的循环来连续3次搜索AA的外观

enter image description here

我正在添加一个方法，用户可以通过该方法搜索所有循环并找到该项目。

 local function check_win( matrx_table)

local counter = 1
local term = "AA"
local D = 1

-- for horizontal check for win---
for i = 1, no_rows, 1 do
    for j= 1, no_Columns, 1 do
        if((j+1) <= no_Columns) then             
            if(table_mXn[i][j] == term and table_mXn[i][j+1] == term)then
                counter = counter + 1;
            else
                counter = 1
            end               
            if(counter == 3)then
                return counter
            end               
        end
    end             
end

counter = 1
-- for vertical check for win--
for i = 1, no_Columns, 1 do
    for j= no_rows, 1, -1 do
        if((j-1) >= 1) then             
            if(table_mXn[j][i] == term and table_mXn[j-1][i] == term)then
                counter = counter + 1;
            else
                counter = 1
            end    
            if(counter == 3)then
                return counter
            end               
        end
    end             
end

counter = 1
D = 1
-- for diagonol  left half check for win in figure loop 1--
for m = 1, no_rows, 1 do
    D = 1
    for i =m, no_rows,1 do
        if(i+1 <= no_rows and D+1 <= no_Columns)then
            if(table_mXn[i][D] == term and table_mXn[i+1][D+1] == term)then
                counter = counter + 1;
                print("hhhhh")
            else
                counter = 1
            end               
            if(counter == 3)then
                return counter
            end     
            D = D + 1
        end
    end
end

counter = 1
D = 1
-- for diagonol  right half check for win in figure loop 2--
for m = 1, no_rows, 1 do
    D = m
    for i =1, no_rows,1 do
        if(i+1 <= no_rows and D+1 <= no_Columns)then
            if(table_mXn[i][D] == term and table_mXn[i+1][D+1] == term)then
                counter = counter + 1;
                print("hhhhh")
            else
                counter = 1
            end               
            if(counter == 3)then
                return counter
            end     
            D = D + 1
        end
    end
end

counter = 1
D = 1
-- for diagonol  left half check for win in figure loop 3--
for m = 1, no_rows, 1 do
    D = no_Columns
    for i =m, no_rows,1 do
        if(i+1 <= no_rows and D-1 >= 1)then
            if(table_mXn[i][D] == term and table_mXn[i+1][D-1] == term)then
                counter = counter + 1;
                print("hhhhh")
            else
                counter = 1
            end               
            if(counter == 3)then
                return counter
            end     
            D = D - 1
        end
    end
end

counter = 1
D = 1
-- for diagonol  left half check for win in figure loop 4--
for m = no_Columns, 1, -1 do
    D = m
    for i =1, no_rows,1 do
        if(i+1 <= no_rows and D-1 >= 1)then
            if(table_mXn[i][D] == term and table_mXn[i+1][D-1] == term)then
                counter = counter + 1;
                print("hhhhh")
            else
                counter = 1
            end               
            if(counter == 3)then
                return counter
            end     
            D = D - 1
        end
    end
end

end

现在你可以在课堂上的任何地方调用这个方法，并且可以在该矩阵中检查可搜索项目是否可用，水平，垂直和对角重复顺序。

在MATLAB中选择矩阵的对角元素

3 个答案: