Question

一个初学者的问题：如何将字符串解压缩为参数序列：

'{2}, {1}, {0}'.format(*'abc')      # unpacking argument sequence
'c, b, a'

我不确定如何用更长的单词设置定界符，但是我尝试了camalCase，但没有用

'sir {}, so your family's name is {}, and you were born in {}'.format(*"HmmamKhoujaSyria")
 #'sir Hmmam, so your family's name is Khouja, and were born in Syria'

编辑：如何添加说明符，以便字符串可以被camalCase甚至是空格之类的特定字符分割

Answer 1

对于第二种情况，您需要按驼峰大小写分隔字符串，为此，我们可以使用this neat function。

该函数将返回由驼峰大小写分隔的字符串列表。然后，我们可以用它来打印我们想要的东西。

请注意，如果您的原始字符串少于3个大写字母，则会得到IndexError: tuple index out of range。如果您还有更多，那将不是问题。

from re import finditer

def camel_case_split(identifier):
    matches = finditer('.+?(?:(?<=[a-z])(?=[A-Z])|(?<=[A-Z])(?=[A-Z][a-z])|$)', identifier)
    return [m.group(0) for m in matches]

s = "HmmamKhoujaSyria"
l = camel_case_split(s)
'sir {}, so your family\'s name is {}, and you were born in {}'.format(*l)
#'sir Hmmam, so your family's name is Khouja, and were born in Syria'

如果您希望使用更简单的分隔符（例如空格或逗号）来分隔字符串，则可以使用str.split（）方法。

s = "Hmmam Khouja Syria"
l = s.split(" ")
'sir {}, so your family\'s name is {}, and you were born in {}'.format(*l)
#'sir Hmmam, so your family's name is Khouja, and were born in Syria'

将字符串解压缩为参数序列

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