如何合并两个Expression <func <t,t =“”>

时间:2019-03-19 09:56:25

标签: c# asp.net expression

我有两个这样的表达式:

Expression<Func<T, T> exp1 = x => new T { Id = 1 , Name = "string"}

Expression<Func<T, T> exp2 = x => new T { Age = 21 }

如何合并它们?

结果:

Expression<Func<T, T> exp3 = x => new T { Id = 1 , Name = "string" , Age = 21}

T是:IEntityBaseRepository<T> where T : class, IEntityBase, new()

IEntityBase:

public interface IEntityBase
{
    string Id { get; set; }
    string Name { get; set; }
    int Age { get; set; }
}

public virtual async Task UpdateAsync(string id, Expression<Func<T, T>> updateFactory)
{
    Expression<Func<T, T>> updateFactory2 = s => new T { age = 21 };
    //Expression<Func<T, T>> updateFactoryFinal = updateFactory + updateFactory2;
    await _context.Set<T>().Where(w => w.Id == id).UpdateAsync(updateFactoryFinal);
}

1 个答案:

答案 0 :(得分:2)

由于您从不使用Func参数,因此可以简化代码并使用Func<T>。 next方法将两个(或多个)MemberInitExpression合并为一个:

public static Expression<Func<T>> MergeExpressions<T>(params Expression<Func<T>>[] expressions)
  where T : new()
{
    var allBindings = new List<MemberBinding>();
    foreach (var expression in expressions)
    {
        var bindings = ((MemberInitExpression) expression.Body).Bindings;
        allBindings.AddRange(bindings);
    }

    var body = Expression.MemberInit(Expression.New(typeof(T)), allBindings);
    return Expression.Lambda<Func<T>>(body);
}

您可以here在线查看它