Question

我尝试阅读，但仍然不知道如何处理此请求：

我有一张这样的桌子：

False

我想在id_category 5＆8和id_news像id_opinion一样的地方打电话给我，我正在做这句话，但我认为这是不正确的

id_news  id_category   id_opinion   
113      5             152 
112      5             152 
152      8             0 
153      8             0 
114      5             153
115      5             153

谢谢

Answer 1

您需要将OR用于id_category，例如：

SELECT * 
FROM news 
WHERE (id_category = '5' OR id_category='8') AND id_news = id_opinion;

另一种选择是使用IN，例如：

SELECT * 
FROM news 
WHERE id_category IN ('5', '8') AND id_news = id_opinion;

Answer 2

您可以使用IN运算符来过滤ID_category 5和8：

SELECT * 
FROM news 
WHERE id_category IN ('5', '8') AND id_news = id_opinion;

Answer 3

这可能有效。

SELECT c.`id_news` as `newsId`,c.id_category as `Category`,c.id_opinion as `opinion`,d.`id_news` as `newsId1`,d.id_category as `Category1`,d.id_opinion as `opinion1` 
from news as c 
JOIN news as d on c.`id_news` = d.`id_opinion`
where c.id_category in(5,8)

选择同一ID但同一表中不同类别的表

3 个答案: