Question

在我的Web应用程序中，使用以下模型，我有两个表分别为users和paymants：

class User extends Authenticatable
{
    use Notifiable;
    protected $guarded = [
        'id'
    ];

    public function payments()
    {
        return $this->hasMany(Payment::class);
    }
}

class Payments extends Model
{
    protected $table = 'payments';
    protected $guarded = ['id'];

    public function users()
    {
        return $this->belongsTo(User::class);
    }
}

每个用户都有很多付款记录，每个付款都属于一个用户，现在我通过查找用户来创建简单的付款记录

$user = User::find(2);

$user->payments()->create(
    [
        'resnumber' => 'dwwe',
        'price' => '1111',
        'invoice_id' =>'asdasd',
        'month_key' => 'k8Cv2YfuO4jOLXd',
        'month_id' => 6,
        'payment' => false
    ]
);

此代码可以正常工作，并且可以创建成功的付款记录，现在我想例如通过关系船来获取此保存的记录：

$data = $user::with(['payments'])->first();

结果为空：

  #relations: array:2 [▼
    "payments" => Collection {#367 ▼
      #items: []
    }

完整的测试代码：

Route::get('/testPayment', function () {
    $user = User::find(2);

    $user->payments()->create(
        [
            'resnumber' => 'dwwe',
            'price' => '1111',
            'invoice_id' =>'asdasd',
            'month_key' => 'k8Cv2YfuO4jOLXd',
            'month_id' => 6,
            'payment' => false
        ]
    );

    $data = $user::with(['payments'])->first();
    dd($data);
});

迁移代码：

public function up()
{
    Schema::create('payments', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('user_id')->unsigned();
        $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
        $table->integer('month_id')->unsigned();
        $table->foreign('month_id')->references('id')->on('months')->onDelete('cascade');
        $table->string('month_key');
        $table->string('resnumber');
        $table->string('invoice_id');
        $table->string('price');
        $table->boolean('payment')->default(false);
        $table->string('card_holder')->nullable();
        $table->string('result_code')->default(0);
        $table->timestamps();
    });
}

现在有大问题

在将mysql数据库中的user_id值例如从2更改为1之后，我得到以下结果：|

  #relations: array:2 [▼
    "payments" => Collection {#378 ▼
      #items: array:1 [▼
        0 => Payment {#375 ▶}
      ]

此付款记录不适用于ID为2的用户

Answer 1

您正在创建一个新的User查询，该查询返回错误的User。

$user = User::find(2);

$user->payments()->create(
    [
        'resnumber' => 'dwwe',
        'price' => '1111',
        'invoice_id' =>'asdasd',
        'month_key' => 'k8Cv2YfuO4jOLXd',
        'month_id' => 6,
        'payment' => false
    ]
);

$data = $user::with(['payments'])->first();
dd($data);

您找到ID为User的{{1}}
您为2创建付款
您查询每User#2个急于加载的User，然后返回第一个

之所以发生这种情况，是因为payments既是$user 也是 User模型。 User 不会说“为此用户付款”，而是说“获取所有$user::with及其付款” –等效于User

您已经对User::with('payments')->first();感兴趣，因此您的代码应如下所示：

User

Laravel保存关系后得到错误的关系结果

1 个答案: