Question

我正在使用 laravel 4.2 。

我有两个模型如下：

class User extends Eloquent{
   protected $table = 'users';

   public function user_card_details(){
        return $this->hasMany('User_card_details');
   }
}

并且

class User_card_details extends Eloquent {

    protected $table = 'user_card_details';

    public $timestamps = true;

    public $softdeletes = true;

    public function user(){
        return $this->belongsTo('User')->first();
    }
}

我可以使用以下方式保存关系记录：

$user_card_details = new User_card_details();
$user_card_details->card_number = Input::get('card_number');
$user_card_details->card_exp_month = Input::get('card_expires_m');
$user_card_details->card_exp_year = Input::get('card_expires_y');
$user_card_details->card_cvv = Input::get('card_cvv');
$user->user_card_details()->save($user_card_details);

到目前为止，它对我来说很好。

在save()之后，我想要用user_details填充用户对象。

因此，如果我想使用这些属性，我可以使用它：

echo $user->user_card_details->card_number;

但现在不行。

有什么建议吗？

由于

Answer 1

您必须删除()才能获得实际的模型或集合：

echo $user->user_card_details->card_number;

当您调用实际功能时，您将收到“查询”构建器的实例。

此外，在您尝试将其绑定到用户之前，您似乎没有保留$user_card_details - 对象：

$user_card_details = new User_card_details();
$user_card_details->card_number = Input::get('card_number');
$user_card_details->card_exp_month = Input::get('card_expires_m');
$user_card_details->card_exp_year = Input::get('card_expires_y');
$user_card_details->card_cvv = Input::get('card_cvv');
$user_card_details->save(); //Added this line.

$user->user_card_details()->save($user_card_details);

更正确的方法是：

$user_card_details = [
        'card_number'    => Input::get( 'card_number' ),
        'card_exp_month' => Input::get( 'card_expires_m' ),
        'card_exp_year'  => Input::get( 'card_expires_y' ),
        'card_cvv'       => Input::get( 'card_cvv' ),
    ];

$userCardDetailObj = $user->user_card_details()->create( $user_card_details );

现在，您的User_card_detail - 实例将作为返回的对象提供。

Laravel在save（）之后得到对象内的关系模型

1 个答案: