春季集成:SimpleAsyncTaskExecutor

时间:2019-03-14 18:24:38

标签: spring-integration spring-integration-dsl

我已经在这个网站上阅读了另一个这样的问题,但我不知道如何解决该问题。

Spring Integration: Application leaking SimpleAsyncTaskExecutor threads?

我的错误类似于上一个链接

SimpleAsyncTaskExecutor-2327" - Thread t@2405
java.lang.Thread.State: WAITING
    at sun.misc.Unsafe.park(Native Method)
    - parking to wait for <7a224c1> (a java.util.concurrent.CountDownLatch$Sync)
    at java.util.concurrent.locks.LockSupport.park(LockSupport.java:175)
    at java.util.concurrent.locks.AbstractQueuedSynchronizer.parkAndCheckInterrupt(AbstractQueuedSynchronizer.java:836)
    at java.util.concurrent.locks.AbstractQueuedSynchronizer.doAcquireSharedInterruptibly(AbstractQueuedSynchronizer.java:997)
    at java.util.concurrent.locks.AbstractQueuedSynchronizer.acquireSharedInterruptibly(AbstractQueuedSynchronizer.java:1304)
    at java.util.concurrent.CountDownLatch.await(CountDownLatch.java:231)
    at org.springframework.messaging.core.GenericMessagingTemplate$TemporaryReplyChannel.receive(GenericMessagingTemplate.java:199)
    at org.springframework.messaging.core.GenericMessagingTemplate$TemporaryReplyChannel.receive(GenericMessagingTemplate.java:192)
    at org.springframework.messaging.core.GenericMessagingTemplate.doReceive(GenericMessagingTemplate.java:130)
    at org.springframework.messaging.core.GenericMessagingTemplate.doSendAndReceive(GenericMessagingTemplate.java:157)
    at org.springframework.messaging.core.GenericMessagingTemplate.doSendAndReceive(GenericMessagingTemplate.java:45)
    at org.springframework.messaging.core.AbstractMessagingTemplate.sendAndReceive(AbstractMessagingTemplate.java:42)
    at org.springframework.integration.core.MessagingTemplate.sendAndReceive(MessagingTemplate.java:97)
    at org.springframework.integration.core.MessagingTemplate.sendAndReceive(MessagingTemplate.java:38)
    at org.springframework.messaging.core.AbstractMessagingTemplate.convertSendAndReceive(AbstractMessagingTemplate.java:79)
    at org.springframework.messaging.core.AbstractMessagingTemplate.convertSendAndReceive(AbstractMessagingTemplate.java:70)
    at org.springframework.integration.gateway.MessagingGatewaySupport.doSendAndReceive(MessagingGatewaySupport.java:449)

我正在使用

  • spring-integration-java-dsl-1.2.3.RELEASE
  • spring-integration-ip-4.3.17.RELEASE
  • spring-integration-http-4.3.17.RELEASE

下一个场景是:我通过Api控制器收到一条消息,并且此消息是通过un TCP套接字发送的。

我已经定义了MessageGateway接口

@MessagingGateway(defaultRequestChannel = "toTcp.input")
public interface MessageTcpGateway {

@Gateway
public ListenableFuture<Void> sendTcpChannel(byte[] data, 
 @Header("connectionId") String connectionId );
}

在这样的服务类中使用此接口之后:

public void sendMessageTcpGateway(final String bridgeId,final String connectionId, final byte[] message) {
    LOGGER.debug("sendMessageTcpGateway connectionId:{} - message:{}", connectionId, message);
    if (holder.existsConnection(connectionId)!=null) {
           gatewayTcp.sendTcpChannel(message,connectionId);
    } else {
        LOGGER.error("Not send message connectionId:{} - message:{}", connectionId, message);
    }
}
  1. 为什么线程正在等待?我的流程是否正在等待任何形式的征兆,而不考虑我?我想如果连接不可用或任何类型的错误,spring-integration将引发异常

  2. 我该如何解决此问题?

1 个答案:

答案 0 :(得分:0)

我想知道为什么不遵循该SO线程的建议... ListenableFuture<Void>是您解决方案的瓶颈。正如您通过堆栈跟踪所看到的那样,这里有doSendAndReceive(),但是我想您的目标解决方案实际上是单向的,并且不为标头中的replyChannel返回任何内容。

您应该考虑使用普通的void返回类型和下游的ExecutorChannel

不幸的是,由于网关方法的Future返回类型指示您将要执行请求-响应异步方式,因此我们无法从框架方面检测到这种情况。在您的情况下,这只是一个异步请求,仅此而已。