我们正在生产弹簧应用程序,似乎它正在泄漏线程。
当我进行线程转储时,我看到以下似乎在等待的线程。以下是一个示例,但有数千个
"SimpleAsyncTaskExecutor-1801" prio=10 tid=0x00007fa668413800 nid=0x376c waiting on condition [0x00007fa4fbaff000]
java.lang.Thread.State: WAITING (parking)
at sun.misc.Unsafe.park(Native Method)
- parking to wait for <0x00000007777e2ba8> (a java.util.concurrent.CountDownLatch$Sync)
at java.util.concurrent.locks.LockSupport.park(LockSupport.java:186)
at java.util.concurrent.locks.AbstractQueuedSynchronizer.parkAndCheckInterrupt(AbstractQueuedSynchronizer.java:834)
at java.util.concurrent.locks.AbstractQueuedSynchronizer.doAcquireSharedInterruptibly(AbstractQueuedSynchronizer.java:994)
at java.util.concurrent.locks.AbstractQueuedSynchronizer.acquireSharedInterruptibly(AbstractQueuedSynchronizer.java:1303)
at java.util.concurrent.CountDownLatch.await(CountDownLatch.java:236)
at org.springframework.integration.core.MessagingTemplate$TemporaryReplyChannel.receive(MessagingTemplate.java:415)
at org.springframework.integration.core.MessagingTemplate$TemporaryReplyChannel.receive(MessagingTemplate.java:409)
at org.springframework.integration.core.MessagingTemplate.doReceive(MessagingTemplate.java:317)
at org.springframework.integration.core.MessagingTemplate.doSendAndReceive(MessagingTemplate.java:341)
at org.springframework.integration.core.MessagingTemplate.sendAndReceive(MessagingTemplate.java:255)
at org.springframework.integration.core.MessagingTemplate.convertSendAndReceive(MessagingTemplate.java:290)
at org.springframework.integration.gateway.MessagingGatewaySupport.doSendAndReceive(MessagingGatewaySupport.java:224)
at org.springframework.integration.gateway.MessagingGatewaySupport.sendAndReceive(MessagingGatewaySupport.java:203)
at org.springframework.integration.gateway.GatewayProxyFactoryBean.invokeGatewayMethod(GatewayProxyFactoryBean.java:306)
at org.springframework.integration.gateway.GatewayProxyFactoryBean.doInvoke(GatewayProxyFactoryBean.java:269)
at org.springframework.integration.gateway.GatewayProxyFactoryBean.access$200(GatewayProxyFactoryBean.java:71)
at org.springframework.integration.gateway.GatewayProxyFactoryBean$AsyncInvocationTask.call(GatewayProxyFactoryBean.java:499)
at java.util.concurrent.FutureTask.run(FutureTask.java:262)
at java.lang.Thread.run(Thread.java:745)
最终,它会导致服务器无响应,只有重启才能恢复。
这似乎涉及一个发送消息的Spring Integration Gateway,并且正在等待它永远不会得到的答案。我们的应用程序中唯一使用此功能的地方是使用服务接口将这些消息发送(发布)到RabbitMQ交换的通知通道
这是服务接口代码:
@Component
public interface INotificationSender {
Future<Void> sendNotification(@Payload Object notification,
@Header("routingKey") String routingKey,
@Header("notificationType") String type);
}
这是相关的弹簧配置:
<!-- Spring Integration RabbitMQ adapter -->
<rabbit:template
id="amqpTemplate"
connection-factory="notificationConnectionFactory" />
<rabbit:connection-factory
id="notificationConnectionFactory"
addresses="${notificationChannel.rabbitHost1}:${notificationChannel.rabbitPort}, ${notificationChannel.rabbitHost2}:${notificationChannel.rabbitPort}"
username="${notificationChannel.rabbitUsername}"
password="${notificationChannel.rabbitPassword}"
virtual-host="${notificationChannel.rabbitVirtualHost}"/>
<rabbit:topic-exchange
name="notificationExchange"/>
<!-- Spring Integration AMQP -->
<int-amqp:outbound-channel-adapter
id="notificationChannelAdapter"
channel="notificationChannelEnc"
exchange-name="notificationExchange"
routing-key-expression="headers['routingKey']"
mapped-request-headers="STANDARD_REQUEST_HEADERS, notificationType"/>
<!-- Spring Integration Core -->
<int:channel
id="notificationChannelEnc">
<int:interceptors>
<int:wire-tap channel="loggingChannel" />
</int:interceptors>
</int:channel>
<int:channel id="notificationChannel"/>
<int:object-to-json-transformer
id="NotificationEncoder"
content-type="text/x-json"
input-channel="notificationChannel"
output-channel="notificationChannelEnc"/>
<int:gateway
id="notificationGateway"
default-request-channel="notificationChannel"
service-interface="com.ericsson.ericloud.commander.notification.sender.INotificationSender"/>
我们使用的是Spring版本3.2.3.RELEASE和Spring Integration版本3.0.0.M2
任何人都知道如何处理这个并让这些线程正确终止?
谢谢, /塞巴斯蒂安
答案 0 :(得分:1)
您的Future<Void>
是瓶颈。
我猜你想要异步发送通知,不要等待任何回复。
但无论如何Gateway
尝试等待回复,因为它将Future
视为启动异步过程的提示。
要克服它,您必须将回报更改为简单void
并使用ExecutorChannel
作为网关default-request-channel
。
查看Reference Manual中的更多信息。