所有spring mvc + hibernate + spring安全示例都说我需要创建MyUserService类,该类从springSecurity扩展UserDetailsService来将我的数据库与spring security绑定在一起。 但是,当我这样做时,我得到:创建名称为“ webSecurityConfig”的bean时出错,未定义此类bean UserSerivce,因为当我尝试将其自动连接到SecurityConfig时,它尚不存在。 当我下载任何在线示例时,都给我同样的错误。
My project in Git-start_over分支。
我的WebSecurityConfig类:
@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private UserService userService;
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userService).passwordEncoder(passwordEncoder());
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().antMatchers("/login", "/").anonymous()
.antMatchers("/admin", "/admin**").hasRole("ADMIN")
.anyRequest().authenticated()
.and()
.formLogin().loginPage("/login").permitAll()
.and()
.logout().logoutSuccessUrl("/login").permitAll()
.and()
.csrf().disable();
}
@Bean
public PasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
}
我的UserService:
public interface UserService extends UserDetailsService {
void save(User user);
List<User> getAllUsers();
}
我的UserServiceImpl
@Service
public class UserServiceImp implements UserService{
@Autowired
private UserDao userDao;
@Transactional
public void save(User user) {
userDao.save(user);
}
@Transactional(readOnly = true)
public List<User> getAllUsers() {
return userDao.getAllUsers();
}
@Transactional(readOnly=true)
@Override
public UserDetails loadUserByUsername(final String username)
throws UsernameNotFoundException {
com.rjproject.entities.User user = userDao.findByUserName(username);
List<GrantedAuthority> authorities =
buildUserAuthority(user.getAuthorities());
return buildUserForAuthentication(user, authorities);
}
private org.springframework.security.core.userdetails.User buildUserForAuthentication(com.rjproject.entities.User user,
List<GrantedAuthority> authorities) {
return new org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(),
user.isEnabled(), true, true, true, authorities);
}
private List<GrantedAuthority> buildUserAuthority(Set<Authorities> userRoles) {
Set<GrantedAuthority> setAuths = new HashSet<GrantedAuthority>();
// Build user's authorities
for (Authorities userRole : userRoles) {
setAuths.add(new SimpleGrantedAuthority(userRole.getAuthority()));
}
List<GrantedAuthority> Result = new ArrayList<GrantedAuthority>(setAuths);
return Result;
}
}
UPD:
我有RunJob类,该类在启动时创建用户,并且在那里自动连接UserService且没有错误。在这里:
@Service
public class RunJob implements InitializingBean {
private static final Logger logger = Logger.getLogger(RunJob.class);
@Autowired
private UserService userService;
public void afterPropertiesSet() {
User userA = new User();
userA.setUsername("ARS");
userA.setPassword("ART");
Authorities authorityA = new Authorities();
authorityA.setAuthority("ADMIN");
authorityA.setUser(userA);
Set<Authorities> roles = new HashSet<>();
roles.add(authorityA);
userA.setAuthorities(roles);
userService.save(userA);
logger.info("user " + userA.getUsername() + " " + userA.getPassword() + " is saved with " + authorityA.getAuthority() + " authority");
User userB = new User();
userB.setUsername("John");
userB.setPassword("Doe");
Authorities authorityB = new Authorities();
authorityB.setAuthority("USER");
authorityB.setUser(userB);
roles.clear();
roles.add(authorityB);
userB.setAuthorities(roles);
userService.save(userB);
logger.info("user " + userB.getUsername() + " " + userB.getPassword() + " is saved with " + authorityB.getAuthority() + " authority");
}
}
下载任何在线示例时,我都会得到完全相同的错误。 SpringSecurity本身。 UPD2: 这是所有配置类。
webMvcConfig
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = {"com.rjproject"})
public class WebMvcConfig implements WebMvcConfigurer {
@Autowired
private ApplicationContext applicationContext;
@Bean
public SpringResourceTemplateResolver templateResolver() {
SpringResourceTemplateResolver templateResolver = new SpringResourceTemplateResolver();
templateResolver.setApplicationContext(applicationContext);
templateResolver.setPrefix("/WEB-INF/templates/");
templateResolver.setSuffix(".html");
templateResolver.setTemplateMode(TemplateMode.HTML);
templateResolver.setCacheable(true);
return templateResolver;
}
@Bean
public SpringTemplateEngine templateEngine() {
SpringTemplateEngine templateEngine = new SpringTemplateEngine();
templateEngine.setTemplateResolver(templateResolver());
templateEngine.setEnableSpringELCompiler(true);
return templateEngine;
}
@Bean
public ViewResolver viewResolver() {
ThymeleafViewResolver viewResolver = new ThymeleafViewResolver();
viewResolver.setTemplateEngine(templateEngine());
return viewResolver;
}
@Override
public void addResourceHandlers(final ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
}
}
WebAppInit
public class WebAppInit extends AbstractAnnotationConfigDispatcherServletInitializer {
@Override
protected Class<?>[] getRootConfigClasses() {
return new Class[] { HibernateConfig.class, WebSecurityConfig.class};
}
@Override
protected Class<?>[] getServletConfigClasses() {
return new Class[] { WebMvcConfig.class};
}
@Override
protected String[] getServletMappings() {
return new String[]{"/"};
}
}
答案 0 :(得分:0)
1:在您的情况下(javaconfig),您必须定义一个返回userService
对象的Bean,它在哪里定义?!
2:换句话说,我想如果您在userService
类中为WebSecurityConfig
添加了setter方法,那么问题就解决了!就是这样
public void setUserService(UserService userService){
this.userService = userService;
}
下一步,在UserService
接口中实现类,您必须在类上方添加@Service
批注,并将@Service
的'value'属性设置为“ userService”。>