Question

我正在尝试使EVENTNAME数组中的值成为其下方数组的键。

我希望能够在php变量上进行foreach并获取EVENTNAME及其迁移，效果和供应链的计数。

$keyevents = oci_parse($conn, "SELECT EVENTNAME FROM KEYEVENTS GROUP BY EVENTNAME");
oci_execute($keyevents);
oci_fetch_all($keyevents, $keyevent);

$immigrations = oci_parse($conn, "SELECT COUNT(*) IMMIGRATIONS FROM KEYEVENTS LEFT JOIN IMMIGRATION ON KEYEVENTS.EVENTID = IMMIGRATION.EVENTID GROUP BY EVENTNAME");
oci_execute($immigrations);
oci_fetch_all($immigrations, $imm);

$effects = oci_parse($conn, "SELECT COUNT(*) EFFECTS FROM KEYEVENTS LEFT JOIN EFFECT ON KEYEVENTS.EVENTID = EFFECT.EVENTID GROUP BY EVENTNAME");
oci_execute($effects);
oci_fetch_all($effects, $eff);

$supplychains = oci_parse($conn, "SELECT COUNT(*) SUPPLYCHAINS FROM KEYEVENTS LEFT JOIN SUPPLYCHAINS ON KEYEVENTS.EVENTID = SUPPLYCHAINS.EVENTID GROUP BY EVENTNAME");
oci_execute($supplychains);
oci_fetch_all($supplychains, $supp);

$stats = array_merge($keyevent, $imm, $eff, $supp);

highlight_string("<?php\n\$stats =\n" . var_export($stats, true) . ";\n?>");

var_export

array (
  'EVENTNAME' => 
  array (
    0 => 'Brexit',
    1 => 'leave date set',
    2 => 'leave date ',
    3 => 'deal or no deal',
  ),
  'IMMIGRATIONS' => 
  array (
    0 => '1',
    1 => '1',
    2 => '1',
    3 => '1',
  ),
  'EFFECTS' => 
  array (
    0 => '2',
    1 => '1',
    2 => '1',
    3 => '2',
  ),
  'SUPPLYCHAINS' => 
  array (
    0 => '1',
    1 => '1',
    2 => '1',
    3 => '1',
  ),
)

Answer 1

我假设您不知道键名，并使用array_keys来找出键名。
然后，我循环第一个子数组，并使用array_column中的键获取其他值。
预期的输出在子数组中不包含关联键，但是如果需要，请使用第二个代码。

$arr = array ( 'EVENTNAME' => array ( 0 => 'Brexit', 1 => 'leave date set', 2 => 'leave date ', 3 => 'deal or no deal', ), 'IMMIGRATIONS' => array ( 0 => '1', 1 => '1', 2 => '1', 3 => '1', ), 'EFFECTS' => array ( 0 => '2', 1 => '1', 2 => '1', 3 => '2', ), 'SUPPLYCHAINS' => array ( 0 => '1', 1 => '1', 2 => '1', 3 => '1', ), );
$keys = array_keys($arr);

foreach($arr[$keys[0]] as $key => $val){
    $result[$val] = array_column(array_slice($arr,1), $key);
}

var_export($result)

输出：

array (
  'Brexit' => 
  array (
    0 => '1',
    1 => '2',
    2 => '1',
  ),
  'leave date set' => 
  array (
    0 => '1',
    1 => '1',
    2 => '1',
  ),
  'leave date ' => 
  array (
    0 => '1',
    1 => '1',
    2 => '1',
  ),
  'deal or no deal' => 
  array (
    0 => '1',
    1 => '2',
    2 => '1',
  ),
)

https://3v4l.org/Seteg

$keys = array_keys($arr);

foreach($arr[$keys[0]] as $key => $val){
    $result[$val] = array_combine(array_slice($keys, 1), array_column(array_slice($arr,1), $key));
}

var_export($result);

输出：

array (
  'Brexit' => 
  array (
    'IMMIGRATIONS' => '1',
    'EFFECTS' => '2',
    'SUPPLYCHAINS' => '1',
  ),
  'leave date set' => 
  array (
    'IMMIGRATIONS' => '1',
    'EFFECTS' => '1',
    'SUPPLYCHAINS' => '1',
  ),
  'leave date ' => 
  array (
    'IMMIGRATIONS' => '1',
    'EFFECTS' => '1',
    'SUPPLYCHAINS' => '1',
  ),
  'deal or no deal' => 
  array (
    'IMMIGRATIONS' => '1',
    'EFFECTS' => '2',
    'SUPPLYCHAINS' => '1',
  ),
)

https://3v4l.org/aPCub

PHP-合并两个以上的数组

1 个答案: