Question

将从foreach循环中输出2个或更多数组。喜欢以下

array1 
    [0] => Array
        (
            [0] => 1207
            [1] => 4
            [2] => haha.mp4
        )

    [1] => Array
        (
            [0] => 1208
            [1] => 4
            [2] => hehe.mp4
        )

array2
   [0] => Array
        (
            [0] => 1209
            [1] => 16
            [2] => SampleVideo.mp4
        )

    [1] => Array
        (
            [0] => 1210
            [1] => 16
            [2] => 295.mp4
        )

我想从这两个数组中获取相同的索引值并合并这些数组。

**FinalArray = array1[0],array2[0],array1[1],array2[1]**

E.g

FinalArray

    [0] => Array
        (
            [0] => 1207
            [1] => 4
            [2] => haha.mp4
        )
    [1] => Array
        (
            [0] => 1209
            [1] => 16
            [2] => SampleVideo.mp4
        )

    [2] => Array
        (
            [0] => 1208
            [1] => 4
            [2] => hehe.mp4
        )


    [3] => Array
        (
            [0] => 1210
            [1] => 16
            [2] => 295.mp4
        )

请帮助如何获取相同的索引值并合并该2个数组。感谢

Answer 1

您可以使用array_column和array_merge进行一次循环来实现此目的，如下所示，

$array1 = array(
    0 => [0 => 1207, 1 => 4, 2 => "haha.mp4"],
    1 => [0 => 1208, 1 => 4, 2 => "hehe.mp4"],
);

$array2 = array(
    0 => [0 => 1209, 1 => 16, 2 => "SampleVideo.mp4"],
    1 => [0 => 1210, 1 => 16, 2 => "295.mp4"],
);

// here I assume that the following array is the output of your foreach loop
$array = [$array1, $array2];
$list = [];
foreach ($array as $key => $value) {
    $list = array_merge($list, array_column($array, $key));
}

print_r($list);

现场演示：https://3v4l.org/2chf5

Answer 2

沙，我来救你胡说八道。此页面上的所有方法都使用太多循环或太多函数。最佳做法如下：

代码：（Demo）

$array1 = array(
    0 => [0 => 1207, 1 => 4, 2 => "haha.mp4"],
    1 => [0 => 1208, 1 => 4, 2 => "hehe.mp4"],
);

$array2 = array(
    0 => [0 => 1209, 1 => 16, 2 => "SampleVideo.mp4"],
    1 => [0 => 1210, 1 => 16, 2 => "295.mp4"],
);

foreach($array1 as $k=>$v){
    $result[]=$v;
    // if $array2 always has a matching key:
    $result[]=$array2[$k];
    // if it is possible that $array2 doesn't have a matching key:
    // if(isset($array2[$k]){$result[]=$array2[$k];}
    //... if you have more arrays to include, just repeat like: $result[]=$array3[$k];
}
var_export($result);

输出：

array (
  0 => 
  array (
    0 => 1207,
    1 => 4,
    2 => 'haha.mp4',
  ),
  1 => 
  array (
    0 => 1209,
    1 => 16,
    2 => 'SampleVideo.mp4',
  ),
  2 => 
  array (
    0 => 1208,
    1 => 4,
    2 => 'hehe.mp4',
  ),
  3 => 
  array (
    0 => 1210,
    1 => 16,
    2 => '295.mp4',
  ),
)

Answer 3

$result = array_merge($array1, $array2);
print_r($result);

自： http://php.net/manual/en/function.array-merge.php

Answer 4

要获得带有元素顺序array0[0],array1[0],array0[1],array1[1]的finalArray，首先计算$max_elements，然后执行嵌套循环，检查该数组中是否存在$i元素：

$arrays = [$array0, $array1];
$max_elements = 0;
foreach($arrays as $array){
    $max_elements = max($max_elements, count($array));
}
$merged = []
for($i = 0; $i < $max_elements; $i++){
    foreach($arrays as $array){
        if($array[$i]){
            $merged[] = $array[$i];
        }
    }
}

PHP合并并重新排列2个或更多数组

4 个答案: