Question

在学习C ++时，我有一个简单的猜测，就是我的数字代码。如您所见，它会选择一个随机数，并让用户猜测并记录尝试次数。

int main(){
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;
   int tries = 0;
   int guess;

   cout << "\tWelcome to Guess my Number\n\n";
   do{
    cout << "Enter a guess: ";
    cin >> guess;
    ++tries;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
    }
   } while(guess != secretNumber);
}

虽然这可以正常工作，但我也希望用户仅进行5次尝试。我可以考虑添加另一个else if语句以确保(tries < 6)。

OR

我可以在do内创建另一个while循环，并确保(tries < 6)。

这里最好的方法是什么？

Answer 1

您可以将条件添加到do-while-loop

int main(){
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;
   int tries = 0;
   int guess;

   cout << "\tWelcome to Guess my Number\n\n";
   do{
    cout << "Enter a guess: ";
    cin >> guess;
    ++tries;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
    }
   } while((guess != secretNumber) && (tries < 6));
}

Answer 2

另一种选择是使用for循环并中断正确答案：

int main(){
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;

   cout << "\tWelcome to Guess my Number\n\n";
   for ( int tries = 1; tries < 6; tries++ ) {
    int guess;
    cout << "Enter a guess: ";
    cin >> guess;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
        break;
    }
   }
}

Answer 3

我不确定是否有最好的方法。如您所说，有两种可能性要么在

时添加条件

while(guess != secretNumber && tries < 6);

或者您可以选择

else if(tries > 5)
{
    cout << "You are out of tries, better luck next time ;) \n"
    break;
}

我希望在while上添加条件的那个。但这是我的个人看法。我遇到一个程序员，如果它想做else并尝试使循环条件保持相对简单。使用更复杂的if / boolean语句，您可以提取具有正确名称的函数。在您的情况下，可以这样

 bool isEndGame(int guess, int secretNumber, int tries)
 {
     return (guess != secretNumber) && (tries < 6);
 }

 int main()
 {
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;
   int tries = 0;
   int guess;

   cout << "\tWelcome to Guess my Number\n\n";
   do{
    cout << "Enter a guess: ";
    cin >> guess;
    ++tries;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
    }
   } while (isEndGame(guess, secretNumber, tries));
}

我认为最后一个是最好的选择。您无需考虑条件，其他程序员现在可以清楚地了解其含义。

猜我的数字c ++ while循环内循环

3 个答案: