Question

所以我正在猜测Python 3中的数字游戏

在整个过程之后，我希望我的while循环生成另一个数字，以便我可以再次开始游戏而无需再次运行该程序。请让我知道我做错了什么，如果您能为我提供一些有关while循环使用方法的见解，将不胜感激。

这是代码：

import random

while True:

    number = random.randint(1, 1000)

    count = 0

    guessed = input("Enter the number you guessed: ")
    count += 1

    if int(guessed) < number:
        print("You guessed too low")
    elif int(guessed) > number:
        print("You guessed too high")
    elif int(guessed) == number:
        print(f'You guessed right and it took you {count} guesses to the right number which is {number}')

Answer 1

不确定您粘贴的代码是否是错字（缩进），但是我可能不小心更改了您的实现。

无论如何，您应该只添加另一个while循环，并在用户正确使用它时添加一个中断条件。

import random
while True:
    number = random.randint(1, 1000)
    count = 0
    while True:                                   # Added, and added another layer of indentation
        guessed = input("Enter the number you guessed: ")
        count += 1

        if int(guessed) < number:
            print("You guessed too low")
        elif int(guessed) > number:
            print("You guessed too high")
        elif int(guessed) == number:
            print(f'You guessed right and it took you {count} guesses to the right number which is {number}')
            break                                 # Added

这样做，代码将不断循环以猜测正确的数字，直到正确为止。然后生成一个新的数字进行猜测。但是，除非添加其他中断条件（例如，设置标志while循环将检查是否突破外循环），否则该代码永远不会结束。

Answer 2

我编写了一些快速代码，提示用户是否要继续玩，然后循环浏览并根据需要继续使用新号码继续游戏。我还修复了一些小错误。您的计数一直在循环中重置，因此它总是会说您在1次尝试中发现了它。

import random

def promptUser():
  user_continue = input("Do you want to continue playing? y/n")
  if (user_continue == 'y'):
    number = random.randint(1, 10)
    game(0, number)

def game(count, number):
  while True:
    guessed = input("Enter the number you guessed: ")
    count += 1

    if int(guessed) < number:
      print("You guessed too low")
    elif int(guessed) > number:
      print("You guessed too high")
    elif int(guessed) == number:
      print(f'You guessed right and it took you {count} guesses to the right number which is {number}')
      promptUser()
      break

promptUser()

而循环并发症猜数字游戏

2 个答案: