Question

我是新手。我的要求面临问题。

我的要求是将嵌套的XML转换为Json

下面是输入文件：

for($month = 1; $month<=ceil($amountPaid/$rent); $month++){
    //For each month there is money for rent (using ceil() to account for fractions)

    assignRentFunction(
        $month,
        // The number of the month

        $rent
        //Show the rent ($rent)

        -
        //Deduct

        max(($month * $rent - $amountPaid),0)
        //Any difference if the whole rent for that month hasn't been paid

        /**
         * This relies on a little hack with the max() function:
         * max($var,0) will return 0 if $var is less than 0.
         * So we check to see if the sum of rent up to that month ($month * $rent)
         * is greater than what was paid ($month * $rent) - $amountPaid.
         * If it isn't because it's wrapped in the max,
         * the net (negative) number will just be shown as nill.
         * If it is, the net positive number will be subtracted
         * from the month's rent.
         **/
    );
}

首选输出如下：

<root>
    <Account>
        <name>name</name>
        <age>age</age>
    </Account>
    <Assets>
        <record>
            <info>info</info>
            <details>details</details>
            <attributes>
                <property>property</property>
            </attributes>
        </record>
        <record>
            <info>info 1</info>
            <details>details 1</details>
            <attributes>
                <property>property 1</property>
            </attributes>
        </record>
    </Assets>
</root>

在{ "root":[ {"account": "records":{ {"name":"name","age":"age"} } }, {"assets": "records":{ "info":"info","details":"details" }, {"attributes":{"property":"property"}} , { "info":"info 1","details 1":"details 1" }, {"attributes":{"property":"property 1"}} } ] }段中，我们将获得Assets条记录，所有记录数据应填充在n内部。

有什么办法可以做到这一点？

您的任何意见都会受到赞赏

Answer 1

更新的代码：

import groovy.json.JsonBuilder
def text = '''
<root>
    <Account>
        <name>name</name>
        <age>age</age>
    </Account>
    <Assets>
        <record>
            <info>info</info>
            <details>details</details>
            <attributes>
                <property>property</property>
            </attributes>
        </record>
        <record>
            <info>info 1</info>
            <details>details 1</details>
            <attributes>
                <property>property 1</property>
            </attributes>
        </record>
    </Assets>
</root>
'''

def toJsonBuilder(xml){
    new groovy.json.JsonBuilder(build(new XmlParser().parseText(xml)))
}
def build(node){
    if (node instanceof String)
        return 
    def map = [ "${node.name()}" : '' ]
    if (!node.children().isEmpty() && !(node.children().get(0) instanceof String)) { 
        map.put("${node.name()}", node.children().collect{build(it)}.findAll{it != null})
    } else if (node.text() != ''){
        map.put("${node.name()}", node.text())
    }
    map
}
println toJsonBuilder(text).toPrettyString()

Groovy：将XML嵌套到Json

1 个答案: