Question

我有一个json文件，其中包含按城市分组的联系信息。我想解析json并创建一个名称和数字列表，但是摆弄一个小时左右后，我无法将其以常规方式使用。

def json = '''{
  "date":"2018-01-04T22:01:02.2125",
  "boston": [
    {
      "name":"bob",
      "phone":"242 123123",
      "ext":"12",
      "email":"bob@boston.com"
    },
    {
      "name":"alice",
      "phone":"212-123-345",
      "ext":"1",
      "email":"alice@boston.com"
    }
  ],
  "chicago": [
    {
      "name":"charlie",
      "phone":"313-232-545",
      "ext":"14",
      "email":"charlie@chicago.com"
    },
    {
      "name":"denise",
      "phone":"414-123-546",
      "ext":"9",
      "email":"denise@chicago.com"
    }
  ]
}'''

我已经尝试了以下主题的一些变体，但到目前为止都失败了。

parsedjson = slurper.parseText(json)
phonelist = []
parsedjson.each{phonelist.add([it['name'],it['phone']])}

Answer 1

使用json时比较棘手，因为您需要查找列表中的值...您可以使用findAll来做到这一点，所以给定json：


def json = '''{
  "date":"2018-01-04T22:01:02.2125",
  "boston": [
    {
      "name":"bob",
      "phone":"242 123123",
      "ext":"12",
      "email":"bob@boston.com"
    },
    {
      "name":"alice",
      "phone":"212-123-345",
      "ext":"1",
      "email":"alice@boston.com"
    }
  ],
  "chicago": [
    {
      "name":"charlie",
      "phone":"313-232-545",
      "ext":"14",
      "email":"charlie@chicago.com"
    },
    {
      "name":"denise",
      "phone":"414-123-546",
      "ext":"9",
      "email":"denise@chicago.com"
    }
  ]
}'''

您可以像当前一样导入JsonSlurper并解析json：

import groovy.json.JsonSlurper

def parsedjson = new JsonSlurper().parseText(json)

然后；

def result = parsedjson.findAll { it.value instanceof List } // Find all entries with a list value
          .values()                                          // Get all the lists
          .flatten()                                         // Merge them into a single list
          .collect { [it.name, it.phone] }                   // grab the name and phone for each

在Groovy中解析嵌套的json对象

1 个答案: