Question

我要删除方括号，如本例所示：

输入文件：file1.json

{ "regex_features": [
      [ // This bracket needs to be removed
        {
          "name": "jobname",
          "pattern": "[A-Z]+-[0-9]"
        },
        {
          "name": "project",
          "pattern": "[A-Z]{4}"
        },
        {
          "name": "summary",
          "pattern": "[a-z]+[a-z]+[a-z]{4}"
        },
        {
          "name": "description",
          "pattern": "[a-z]+[a-z]+[a-z]+[a-z]{4}"
        }
      ] // this bracket needs to be removed. 
     ]
}

请提出建议。

Answer 1

假设您有这个文件。json：

{
  "name": "foo",
  "regex_features": [
    [
      {
        "name": "jobname",
        "pattern": "[A-Z]+-[0-9]"
      },
      {
        "name": "project",
        "pattern": "[A-Z]{4}"
      }
    ]
  ]
}

您可以使用更新分配运算符将列表替换为其第一个元素（内部列表）：

jq '.regex_features|=.[0]' file.json

输出：

{
  "name": "foo",
  "regex_features": [
    {
      "name": "jobname",
      "pattern": "[A-Z]+-[0-9]"
    },
    {
      "name": "project",
      "pattern": "[A-Z]{4}"
    }
  ]
}

Answer 2

这是使用 jtc Unix实用程序的替代解决方案：

bash $ <file1.json jtc -w'[0][0]' -w[0] -s
{
   "regex_features": [
      {
         "name": "jobname",
         "pattern": "[A-Z]+-[0-9]"
      },
      {
         "name": "project",
         "pattern": "[A-Z]{4}"
      },
      {
         "name": "summary",
         "pattern": "[a-z]+[a-z]+[a-z]{4}"
      },
      {
         "name": "description",
         "pattern": "[a-z]+[a-z]+[a-z]+[a-z]{4}"
      }
   ]
}
bash $

或另一种方式：bash $ <file1.json jtc -w'[0]' -u'[0][0]'

如何使用jq从Linux中的json文件中的特定位置删除方括号

2 个答案: