Question

变量$ rds_host包含我需要删除的方括号。以下userdate是在创建EC2实例期间运行的amazon ec2控制台的一部分。

        rds_host=`aws rds --region ca-central-1 describe-db-instances --query "DBInstances[*].Endpoint.Address"`



UserData="""#!/bin/bash
            yum update –y
            yum install httpd php mysql php-mysql git -y

            echo "<?php phpinfo(); ?>" > /var/www/html/phpinfo.php
            cd /var/www/html
            echo "<?php phpinfo(); ?>" > /var/www/html/hello.php

            rds_host=`aws rds --region ca-central-1 describe-db-instances --query "DBInstances[*].Endpoint.Address"`


            echo "<?php " >/var/www/html/dbinfo.php  

            $final_str = [];
            $rds_host = preg_match_all('`"([^"]*)"`',$rds_host, $final_str);
            echo $rds_host
            $rds_host = $rds_host[1]
            echo $rds_host


            echo $rds_host;
            echo "define('DB_SERVER', $rds_host);" >> /var/www/html/dbinfo.php

            echo "define('DB_USERNAME', 'RdsDarius1');" >> /var/www/html/dbinfo.php
            echo "define('DB_PASSWORD', 'RdsDarius1');" >> /var/www/html/dbinfo.php
            echo "define('DB_DATABASE', 'RdsDarius1');" >> /var/www/html/dbinfo.php
            echo "\$connection = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);">> /var/www/html/dbinfo.php
            echo "if (mysqli_connect_errno()) echo "Failed to connect to MySQL: " . mysqli_connect_error();">> /var/www/html/dbinfo.php
            echo "Successfully connected to the RDS instance; $rds_host" >> /var/www/html/dbinfo.php
            echo "?>" >> dbinfo.php

            echo $rds_host
            """

创建输出文件时，它包含不好的括号。

<?php
define('DB_SERVER', [
    "rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
]);
define('DB_USERNAME', 'RdsDarius1');
define('DB_PASSWORD', 'RdsDarius1');
define('DB_DATABASE', 'RdsDarius1');
$connection = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
if (mysqli_connect_errno()) echo Failed to connect to MySQL:  . mysqli_connect_error();
Successfully connected to the RDS instance; [
    "rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
]
?>

我需要以某种方式摆脱服务器名称周围的括号。

<?php
define('DB_SERVER',"rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com");
define('DB_USERNAME', 'RdsDarius1');
define('DB_PASSWORD', 'RdsDarius1');
define('DB_DATABASE', 'RdsDarius1');
$connection = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
if (mysqli_connect_errno()) echo Failed to connect to MySQL:  . mysqli_connect_error();
Successfully connected to the RDS instance;"rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
?>

Answer 1

你有数组，所以只是破坏结果

$rds_host = [
    "rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
] 
$rds_host = implode('', $rds_host);
echo $rds_host;

Answer 2

应该有效：

$final_str = [];
preg_match_all('`"([^"]*)"`',$rds_host, $final_str);
$final_str[1];//this is what you want

Answer 3

如果我理解你的问题，你需要从字符串中获取方括号内的内容。

你可以使用正则表达式

$rds_host = '[
    "rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
]';
 preg_match_all("/\[([^\]]*)\]/", $rds_host, $matches);
echo str_replace('"', '',($matches[1][0]));

如果你讨厌正则表达式，这里有一种不推荐的评估方式

$rds_host = '[
    "rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"
]';


//echo $str. "\n";
eval("\$rds_host = \"$rds_host\";");
echo $str_final=(json_decode($rds_host)[0]);

Answer 4

假设您不能只使用$rds_host[0]
你可以使用json_encode对数组进行字符串化，然后删除括号。

$rds_host = ["rdsdarius1.c6pbnndp0mmz.ca-central-1.rds.amazonaws.com"];
$rds_host = str_replace(array('[', ']',), '', json_encode($rds_host));

Answer 5

我必须在原始字符串中将*替换为0才能仅检索值。

这是最终结果。（见0代替*）

rds_host=`aws rds --region ca-central-1 describe-db-instances --query "DBInstances[0].Endpoint.Address"`

如何从php文件中的字符串中删除方括号？

5 个答案: