我在Node js中的异步功能和回调有问题。我需要获取我朋友的所有帖子并显示出来。但是,如果我没有setTimeout()进行操作,它将仅返回部分数据。不设置setTimeout怎么解决这个问题?当然,等待5-6或10秒来获取所有数据是荒谬的。我也尝试了Promises,但是再次回答是不完整的。请有人可以帮助我吗?
//Sending request with axios to Controller
axios.post(packages.proxy+'users/getFriendsPosts',{id: user_id},config)
.then(res => {
// Code for displaying result
})
//User Controller
router.post("/getFriendsPosts", getFriendsPosts);
//Send request body to userService.js
function getFriendsPosts(req, res, next) {
userService.getFriendsPosts(req.body, function(posts, user){
res.json({posts,user});
})
.catch(err => next(err));
}
//userService.js
module.exports = {
getFriendsPosts,
};
async function getFriendsPosts(user,callback){
var arr = [];
var array = [];
MongoClient.connect(url, async function(errr, db) {
if (errr) throw errr;
var dbo = db.db("drone-x");
//Find user
dbo.collection("users").find({_id: ObjectId(user.id)}).toArray(async function(err, result) {
if (err) throw err;
result.forEach(async function(element, index) {
if(element.friends.length != 0){
element.friends.forEach(async function(elem) {
//Find user's friends
dbo.collection("users").find({_id: ObjectId(elem.id)}).toArray(async function(error, res) {
if (error) throw error;
//push user's friends to arr
arr.push(res);
res.forEach(async function(elements) {
//Find user's friends posts
dbo.collection("posts").find({userId: elements._id.toString()}).toArray(async function(errors, results) {
if (errors) throw errors;
//push user's friends posts to array
array.push(results);
//callback results through setTimeout
setTimeout(async function(){ await callback(array, arr); db.close(); }, 2000);
});
});
});
});
}
else
{
await callback("0");
}
});
});
});
}
如果我不使用setTimeout函数,它将仅返回2-3个数据,但是对于setTimeout,它将返回所有数据。如果要提高数据,那么我需要增加setTimeout时间。但这当然不是一个好主意。有人可以帮助我吗?
答案 0 :(得分:0)
您应在此代码中使用try catch
getFriendsPosts = async (user,callback) => {
const arr = [];
const array = [];
const db = await MongoClient.connect(url);
const dbo = db.db("drone-x");
const results = await dbo.collection("users").find({_id: ObjectId(user.id)})
const resultPromise = _.map(results, async element => {
const friends = _.get(element, 'friends', [])
if(friends.length != 0) {
const friendPromise = _.map(friends, async friend => {
const ress = await dbo.collection("users").find({_id: ObjectId(friend.id)})
arr.push(ress);
const resPromise = _.map(ress, async res => {
const posts = await dbo.collection("posts").find({userId: res._id.toString()})
const postPromise = _.map(posts, post => {
array.push(post);
})
await Promise.all(postPromise)
})
await Promise.all(resPromise)
})
await Promise.all(friendPromise)
}
})
await Promise.all(resultPromise)
return { arr , array }
}
我不建议这样花费太多时间。您应该使用猫鼬,并对较长的查询使用聚合。