Question

我在mongodb中有以下收藏集

db.orders.find()

{ "_id" : ObjectId("5cc69ad493297eade15bacb7"), "item" : "card", "qty" : 15, "user_mob" : 8220097 }
{ "_id" : ObjectId("5cc69adf93297eade15bacb8"), "item" : "card1", "qty" : 11, "user_mob" : 8220097 }

db.items.find()

{ "_id" : ObjectId("5cc69ba493297eade15bacbc"), "item" : "card1", "color" : "blue", "weight" : "50g" }
{ "_id" : ObjectId("5cc69bb793297eade15bacbd"), "item" : "card", "color" : "yellow", "weight" : "60g" }
{ "_id" : ObjectId("5cc69bd193297eade15bacbe"), "item" : "ball", "color" : "multi color", "weight" : "140g" }
{ "_id" : ObjectId("5cc69be793297eade15bacbf"), "item" : "footer", "color" : "Black", "weight" : "340g" }
{ "_id" : ObjectId("5cc69c0c93297eade15bacc0"), "item" : "caps", "color" : "multi color", "weight" : "250g" }

db.users_nippon.find()

{ "_id" : ObjectId("5cadf1d9b0a2d18bdc6de90a"), "name" : "hariharan", "mobile_no" : "8220097", "role_id" : "2", "language_code" : "ml", "encrypted_password" : "password_Passw0rd", "is_salesman" : "true", "is_mobile" : "true" }

然后我在节点js中编写代码以从上述所有表中获取数据。代码是...

db.collection('users_nippon').aggregate([
            {
                $lookup: {
                   from: "orders",
                   localField: "mobile_no",
                   foreignField: "user_mob",
                   as: "orders_data"
                }
            },
            {
                $unwind: "$orders_data"
            },
            {
                $lookup: {
                    from: "items",
                    localField: "item",
                    foreignField: "item",
                    as: "items_data"
                }
            },
            {
                $unwind: "$items_data"
            }
        ]).toArray(function(err, list) {
            if (err) throw err;
            console.log(JSON.stringify(list));
            res.send(JSON.stringify(list));
            });

出了点问题。它返回空（ [] ）。

所以，请帮助我解决此问题。

下面的代码是我想要的输出的示例

[
{
    "_id": "5cc67e439c26e35a70fddfd5",
    "name": "hariharan",
    "mobile_no": "8220097",
    "role_id": "2",
    "language_code": "ml",
    "encrypted_password": "password_Passw0rd",
    "is_salesman": "true",
    "is_mobile": "true",
    "orders_data": {
        "_id": "5cc6ebe9f4c1d9080b93b013",
        "item": "card",
        "qty": 15,
        "user_mob": "8220097",
        "items_data": {
                "_id": "5cc69bb793297eade15bacbd",
                "item": "card",
                "color": "yellow",
                "weight": "60g"
          }
    }

}]

Answer 1

您的查询中有2个问题：

字段user_mob（订单模式）是Number，而mobile_no（user_nippon模式）是String，因此无法进行查找。您可能想对这些字段使用相同的类型。
第二个lookup不正确。前lookup和unwind返回item元素内的orders_data元素，因此此localField的{{1}}应更改为：{{ 1}}

因此，在将lookup和orders_data.item都更改为具有匹配类型之后，查询将如下所示：

user_mob

Answer 2

您必须将mobile_no集合中的users_nippon的数据类型从string更改为NumberLong，否则$lookup将不起作用。更正它之后，现在您可以使用下面的聚合查询以所需的相同格式获得所需的结果。

db.collection('users_nippon').aggregate([

        {
            $lookup: {
              from: "orders",
              localField: "mobile_no",
              foreignField: "user_mob",
              as: "orders_data"
            }
        },
        {
            $unwind: "$orders_data"
        },
        {
            $lookup: {
                from: "items",
                localField: "orders_data.item",
                foreignField: "item",
                as: "orders_data.items_data"
            }
        },
        {
            $unwind: "$orders_data.items_data"
        }
    ]).toArray(function(err, list) {
        if (err) throw err;
        console.log(JSON.stringify(list));
        res.send(JSON.stringify(list));
        });

这是经过测试的有效解决方案。

如何使用节点js从mongodb的3个集合中获取数据？

2 个答案: