PHP找到最便宜的排列

时间:2019-03-07 01:13:06

标签: php algorithm math search

我有多个产品都有相同的尺寸,我需要找到满足最小尺寸要求的最便宜的配置。

例如,约翰至少需要10升的存储空间-可以更多,但不能更少。

有2L,3L,5L,8L和10L选项(但这可以更改)。

例如,获得它可能更便宜:

  • 1x10L容器或
  • 2x5L容器或
  • 1x2L,1x3L和1x5L或
  • 4x3L(这个超过10 L,但它仍然有可能会更便宜)

到目前为止,我已经尝试了多达4次的循环(因为通常最大需求为40 L),但是在某些情况下,我的内存已用完,这似乎并不是最有效的的方式。


// Size is in mL

$available_containers = [
[
  'id' => 22700,
  'price' => 1190,
  'size' => 2000,
],
[
  'id' => 22701,
  'price' => 1245,
  'size' => 3000,
],
[
  'id' => 22702,
  'price' => 1415,
  'size' => 4000,
],
[
  'id' => 22715,
  'price' => 12300,
  'size' => 5000,
],
[
  'id' => 22706,
  'price' => 1740,
  'size' => 5000,
],
[
  'id' => 22703,
  'price' => 1510,
  'size' => 5000,
],
[
  'id' => 22707,
  'price' => 1790,
  'size' => 6000,
],
[
  'id' => 22704,
  'price' => 1770,
  'size' => 6000,
],
[
  'id' => 22708,
  'price' => 2215,
  'size' => 7000,
],
[
  'id' => 22705,
  'price' => 2195,
  'size' => 8200,
],
[
  'id' => 22709,
  'price' => 2660,
  'size' => 8200,
],
[
  'id' => 22710,
  'price' => 2799,
  'size' => 10000,
],
[
  'id' => 22711,
  'price' => 2910,
  'size' => 12500,
],
[
  'id' => 22712,
  'price' => 3260,
  'size' => 15000,
],
[
  'id' => 22713,
  'price' => 4130,
  'size' => 20000,
],
[
  'id' => 22714,
  'price' => 3770,
  'size' => 27000,
]
];

$required_size = 8; // Can change.
$container_install = 5;

foreach ( $available_containers as $v ){
  foreach ( $available_containers as $v2 ){
    foreach ($available_containers as $v3 ) {
      foreach ( $available_containers as $v4 ){

        $all_configs = [
          [
            'size' => $v['size'],
            'configuration' => [ $v['size'] ],
            'price' => $v['price'],
          ],
          [
            'size' => $v['size'] + $v2['size'],
            'configuration' => [ $v['size'], $v2['size'] ],
            'price' => $v['price'] + $v2['price'] + $container_install,
          ],
          [
            'size' => $v['size'] + $v2['size'] + $v3['size'],
            'configuration' => [ $v['size'], $v2['size'], $v3['size'] ],
            'price' => $v['price'] + $v2['price'] + $v3['price'] + $container_install + $container_install,
          ],
          [
            'size' => $v['size'] + $v2['size'] + $v3['size'] + $v4['size'],
            'configuration' => [ $v['size'], $v2['size'], $v3['size'], $v4['size'] ],
            'price' => $v['price'] + $v2['price'] + $v3['price'] + $v4['price'] + $container_install + $container_install + $container_install,
          ],
        ];


        foreach ( $all_configs as $c ){
          if ( $c['size'] >= $required_size ){
            $configuration[] = array(
              'configuration' => $c['configuration'],
              'size' => $c['size'],
              'price' => $c['price'],
            );
          }
        }
      }
    }
  }
}


// Sort by price.
$sorted_configs = array_sort($configuration, 'price', SORT_ASC); // This function simply sorts all permutations by price

1 个答案:

答案 0 :(得分:0)

好的,有一些要点可以使这些循环减轻重量。必须通过分而治之的方法解决这个问题。

  1. 创建一个子数组,因为您不需要整个数组,只需一个从1L到10L的新子数组。
  2. 应该按价格从低到高的顺序对子数组进行排序。
  3. 并且仅当第一个指数中的最低价格只能购买一次时,break循环。
  4. 否则,您应该有一个列表,当您已经循环时,该列表将输出。
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