Question

我正在尝试进行鸡尾酒式排序，但是我在行if (a[i] > a[i + 1])上遇到了异常，我不确定为什么。

这是完整的代码。抱歉，这是完全错误的。

import java.util.Arrays;
import java.util.Scanner;

public class Cocktail 
{

public static void main(String[] args) 
{
    Scanner input = new Scanner(System.in);
    int count = 0;
    boolean switched = true;
    int[]a = new int[10];
    for (int i = 0; i < a.length; i++)
    {
        int value = input.nextInt();
        a[i] = value;
    }
    System.out.println(a[0]);
    while (switched == true)
    {
        switched = false;
        for (int i = 0; i < a.length; i++)
        {
            if (a[i] > a[i + 1]) 
            {
                int temp = a[i];
                a[i] = a[i + 1];
                a[i + 1] = temp;
                count++;
                switched = true;
            }
        }
        for (int i = a.length; i >= 0; i++)
        {
            if (a[i] > a[i + 1]) 
            {
                int temp = a[i];
                a[i] = a[i + 1];
                a[i + 1] = temp;
                count++;
                switched = true;
            }
        }
        if (switched == false)
        {
            System.out.println(count);
        }
    }

}

}

Answer 1

您需要更改

if (a[i] > a[i + 1])像这样-> if (i < a.length-1 && a[i] > a[i + 1])。

问题在于它试图到达第11个元素；）

如果可以的话，这是代码的编辑版本：

Scanner input = new Scanner(System.in);
    int count = 0;
    boolean switched = true;


    int[]a = new int[10];
    System.out.println("enter 10 Integers: ");// # Added to make code clearer
    for (int i = 0; i < a.length; i++)
    {

        int value = input.nextInt();
        a[i] = value;
    }
        System.out.println("thankyou, Sorting now!");//# also this one 
    while(switched == true)
    {
        switched = false;
        for (int i = 0; i < a.length; i++)
        {
            if (i < a.length-1 && a[i] > a[i + 1]) // <-- # here was the problem
            {
                int temp = a[i];
                a[i] = a[i + 1];
                a[i + 1] = temp;
                count++;
                switched = true;
            }
        }
        for (int i = a.length; i >= 0; i++)
        {
            if (i < a.length-1 && a[i] > a[i + 1]) //<-- # Also Here 
            {
                int temp = a[i];
                a[i] = a[i + 1];
                a[i + 1] = temp;
                count++;
                switched = true;
            }
        }
        if (switched == false)
        {
            System.out.println("count is "+ count);
        }
    }
    // # added part to print array for testing 
        System.out.println("Sorted Array:");
        for (int i = 0; i <a.length ; i++) {


            System.out.print(a[i]+", ");
        }


    }//main 

}//class

以下是输出：

复制并粘贴，Run and Happy Coding = D

尝试运行鸡尾酒代码Java时超出范围异常

1 个答案: