Question

我是Micronaut框架的新手，我正在尝试使用entitymanager创建我的存储库。我创建了这样的存储库

public interface EmployeeRepository {
    Employee save(@NotNull Employee employee);
    Employee update(@NotNull Employee employee);
    List<Employee> findAll();
    Optional<Employee> findById(@NotNull Long id);
}

并且我使用此类来实现接口并注入entitymanager

@Singleton
public class EmployeeRepositoryImpl implements EmployeeRepository{
    @PersistenceContext
    private EntityManager entityManager;

    public EmployeeRepositoryImpl(@CurrentSession EntityManager entityManager) {
        this.entityManager = entityManager;
    }

    @Override
    @Transactional
    public Employee save(@NotNull Employee employee) {
        entityManager.persist(employee);
        return employee;
    }

    @Override
    @Transactional
    public Employee update(@NotNull Employee employee) {
        return entityManager.merge(employee);
    }

    @Override
    @Transactional(readOnly = true)
    public List<Employee> findAll() {
        String qlString = "SELECT * FROM Employee";
        TypedQuery<Employee> query = entityManager.createQuery(qlString, Employee.class);
        return query.getResultList();
    }

    @Override
    @Transactional(readOnly = true)
    public Optional<Employee> findById(@NotNull Long id) {
        return Optional.ofNullable(entityManager.find(Employee.class, id));
    }
}

问题是我总是遇到此错误：

Message: No bean of type [javax.persistence.EntityManager] exists. Ensure the class is declared a bean and if you are using Java or Kotlin make sure you have enabled annotation processing.
Path Taken: new $EmployeeControllerDefinition$Intercepted([EmployeeRepositoryImpl employeeRepository],BeanContext beanContext,Interceptor[] interceptors) --> new $EmployeeRepositoryImplDefinition$Intercepted([EntityManager entityManager],BeanContext beanContext,Interceptor[] interceptors)
io.micronaut.context.exceptions.DependencyInjectionException: Failed to inject value for parameter [entityManager] of class: com.milamed.dao.$EmployeeRepositoryImplDefinition$Intercepted

PS：我已启用注释处理

Answer 1

对于您的项目，您还没有提供足够的信息来确定缺少的内容，但是我在https://github.com/jeffbrown/mohamedmiledijpa为您创建了一个有效的示例。

https://github.com/jeffbrown/mohamedmiledijpa/blob/master/src/main/java/mohamedmiledijpa/Employee.java

package mohamedmiledijpa;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;

@Entity
public class Employee {

    @Id
    @GeneratedValue
    private Long id;

    private String name;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }
}

https://github.com/jeffbrown/mohamedmiledijpa/blob/master/src/main/java/mohamedmiledijpa/EmployeeRepository.java

package mohamedmiledijpa;

import javax.validation.constraints.NotNull;
import java.util.List;
import java.util.Optional;

public interface EmployeeRepository {
    Employee save(@NotNull Employee employee);
    Employee update(@NotNull Employee employee);
    List<Employee> findAll();
    Optional<Employee> findById(@NotNull Long id);
}

https://github.com/jeffbrown/mohamedmiledijpa/blob/master/src/main/java/mohamedmiledijpa/EmployeeRepositoryImpl.java

package mohamedmiledijpa;

import io.micronaut.configuration.hibernate.jpa.scope.CurrentSession;
import io.micronaut.spring.tx.annotation.Transactional;

import javax.inject.Singleton;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import javax.persistence.TypedQuery;
import javax.validation.constraints.NotNull;
import java.util.List;
import java.util.Optional;

@Singleton
public class EmployeeRepositoryImpl implements EmployeeRepository{
    @PersistenceContext
    private EntityManager entityManager;

    public EmployeeRepositoryImpl(@CurrentSession EntityManager entityManager) {
        this.entityManager = entityManager;
    }

    @Override
    @Transactional
    public Employee save(@NotNull Employee employee) {
        entityManager.persist(employee);
        return employee;
    }

    @Override
    @Transactional
    public Employee update(@NotNull Employee employee) {
        return entityManager.merge(employee);
    }

    @Override
    @Transactional(readOnly = true)
    public List<Employee> findAll() {
        String qlString = "SELECT e FROM Employee e";
        TypedQuery<Employee> query = entityManager.createQuery(qlString, Employee.class);
        return query.getResultList();
    }

    @Override
    @Transactional(readOnly = true)
    public Optional<Employee> findById(@NotNull Long id) {
        return Optional.ofNullable(entityManager.find(Employee.class, id));
    }
}

https://github.com/jeffbrown/mohamedmiledijpa/blob/master/src/main/java/mohamedmiledijpa/EmployeeController.java

package mohamedmiledijpa;

import io.micronaut.http.annotation.Body;
import io.micronaut.http.annotation.Controller;
import io.micronaut.http.annotation.Get;
import io.micronaut.http.annotation.Post;

import java.util.List;

@Controller("/employee")
public class EmployeeController {

    private EmployeeRepository employeeRepository;

    public EmployeeController(EmployeeRepository employeeRepository) {
        this.employeeRepository = employeeRepository;
    }

    @Get("/")
    public List<Employee> list() {
        return employeeRepository.findAll();
    }

    @Post("/")
    public Employee create(@Body Employee employee) {
        return employeeRepository.save(employee);
    }
}

https://github.com/jeffbrown/mohamedmiledijpa/blob/f6500d3fb24190ed59ca64dcc28a02f8069fedfd/build.gradle#L29

compile "io.micronaut.configuration:micronaut-hibernate-jpa"

一切似乎都有效：

~ $ curl http://localhost:8080/employee
[]
~ $ 
~ $ curl -d '{"name":"Jake"}' -H "Content-Type: application/json" -X POST  http://localhost:8080/employee
{"id":1,"name":"Jake"}
~ $ 
~ $ curl -d '{"name":"Zack"}' -H "Content-Type: application/json" -X POST  http://localhost:8080/employee
{"id":2,"name":"Zack"}
~ $ 
~ $ curl http://localhost:8080/employee
[{"id":1,"name":"Jake"},{"id":2,"name":"Zack"}]

Answer 2

我遇到了这个问题，我找到了解决方案：

如果您使用@PersistenceContext 来注入 EntityManger，则需要包含此依赖项：

{使用 Gradle}

compile "io.micronaut.configuration:micronaut-jdbc-hikari"

或 {使用 Maven}

<dependency>
  <groupId>io.micronaut.sql</groupId>
  <artifactId>micronaut-jdbc-hikari</artifactId>
  <scope>compile</scope>
</dependency>

因为这是 micronaut 定位 application.yml 中定义的数据源的方式。

如何在Micronaut上使用entitymanager？

2 个答案: