Question

出于兴趣，我创建（或至少尝试创建）具有四层的人工神经网络作为著名鸢尾花数据集的分类器。作为三种不同花朵的标签，目标值从0到2不等。为了简单起见，我放弃了偏见。

问题是：即使均方误差实际上已减小并且似乎收敛，网络最终还是将所有实例（训练和测试）均等地分类。每次我运行它时，它都是在1到3之间选择一个标签，永远不要低于或高于它。因此，看来梯度下降有些起作用。

可能是由于缺少偏见吗？还是我误解了算法？还是导数不正确？

我在这里学到了反向传播背后的数学理论：https://google-developers.appspot.com/machine-learning/crash-course/backprop-scroll/

neuralnetwork.py

import numpy as np
import math


def sigmoid(x):
    return (math.e**x) / (math.e**x + 1)


def sigmoid_deriv(x):
    return sigmoid(x) * (1 - sigmoid(x))


def ReLU(x):
    return x * (x > 0)


def ReLU_deriv(x):
    if x > 0:
        return 1
    else:
        return 0


def mean_square_error(output_vector, correct_vector):
    error = 0
    for i in range(0, len(output_vector)):
        error += (output_vector[i][0] - correct_vector[i][0])**2
    return 1/len(output_vector) * error


def div_x_output(y, y_correct, nr_instances):
    return 2 / nr_instances * (y - y_correct) * ReLU_deriv(y)

def div_x(y):
    return sigmoid_deriv(y)


def partial_deriv_synapses_output(learning_rate, prediction, solution, nr_instances, x, i, hidden_layer_1):
    return learning_rate * div_x_output(prediction, solution, nr_instances) * hidden_layer_1[x][i]


def partial_deriv_synapses_1(learning_rate, y, i, j, hidden_layer_0):
    return learning_rate * div_x(y) * hidden_layer_0[j][i]


def partial_deriv_synapses_0(learning_rate, y, i, j, input_matrix):
    return learning_rate * div_x(y) * input_matrix[j][i]




class NeuralNetwork:

    def __init__(self, synapses_0, synapses_1, synapses_2):
        self.synapses_0 = synapses_0
        self.synapses_1 = synapses_1
        self.synapses_2 = synapses_2
        self.sigmoid = np.vectorize(sigmoid)
        self.ReLU = np.vectorize(ReLU)

    def fit(self, input_matrix, solutions, learning_rate, nr_instances):
        hidden_layer_0 = self.sigmoid(np.dot(input_matrix, self.synapses_0))
        hidden_layer_1 = self.sigmoid(np.dot(hidden_layer_0, self.synapses_1))
        output_layer = self.ReLU(np.dot(hidden_layer_1, self.synapses_2))

        while mean_square_error(output_layer, solutions) > 0.7:
            print(mean_square_error(output_layer, solutions))
            x = 0
            for prediction in output_layer:
                # back propagate synapses 2
                for i in range(0, len(self.synapses_2)):
                        self.synapses_2[i][0] -= partial_deriv_synapses_output(learning_rate, prediction[0], solutions[x][0], nr_instances, x, i, hidden_layer_1)

                # back propagate synapses 1
                y_deriv_vector_synapses_1 = np.array([1. for i in range(0, len(self.synapses_1[0]))])
                for i in range(0, len(self.synapses_1[0])):
                    y_deriv_vector_synapses_1[i] = div_x_output(prediction[0], solutions[x][0], nr_instances) * self.synapses_2[i][0]
                for i in range(0, len(self.synapses_1)):
                    for j in range(0, len(self.synapses_1[0])):
                        self.synapses_1[i][j] -= partial_deriv_synapses_1(learning_rate, y_deriv_vector_synapses_1[j], i, j, hidden_layer_0)

                # back propagate synapses 0
                y_deriv_vector_synapses_0 = np.array([1. for i in range(0, len(self.synapses_0[0]))])
                for i in range(0, len(self.synapses_0[0])):
                    y_deriv_vector_synapses_0[i] = sum([div_x(y_deriv_vector_synapses_1[k]) * self.synapses_1[i][k] for k in range(0, len(self.synapses_1[0]))])
                for i in range(0, len(self.synapses_0)):
                    for j in range(0, len(self.synapses_0[0])):
                        self.synapses_0[i][j] -= partial_deriv_synapses_0(learning_rate, y_deriv_vector_synapses_0[j], i, j, input_matrix)

                hidden_layer_0 = self.sigmoid(np.dot(input_matrix, self.synapses_0))
                hidden_layer_1 = self.sigmoid(np.dot(hidden_layer_0, self.synapses_1))
                output_layer = self.sigmoid(np.dot(hidden_layer_1, self.synapses_2))

                x += 1

    def predict(self, input_vector):
        hidden_layer_0 = self.sigmoid(np.dot(input_vector, self.synapses_0))
        hidden_layer_1 = self.sigmoid(np.dot(hidden_layer_0, self.synapses_1))
        output_layer = self.ReLU(np.dot(hidden_layer_1, self.synapses_2))

        return output_layer[0]

main.py

from sklearn.datasets import load_iris
from sklearn.model_selection import train_test_split
import numpy as np
import random

from neuralnetwork import NeuralNetwork

iris = load_iris()

X = iris.data
y = iris.target


X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = .2)

network = NeuralNetwork(np.array([[random.random() for i in range(0, 8)] for j in range(0, 4)]),
                        np.array([[random.random() for i in range(0, 3)] for j in range(0, 8)]),
                        np.array([[random.random() for i in range(0, 1)] for j in range(0, 3)]))


network.fit(np.array([x for x in X_train]), np.array([[y] for y in y_train]), 0.1, len(X_train))

error_count = 0
counter = 0

for x in X_train:
    prediction = round(network.predict(x))
    print("prediction: "+ str(prediction) + ", actual: " + str(y_train[counter]))
    if prediction != y_train[counter]:
        error_count += 1
    counter += 1


print("The error count is: " + str(error_count))

感谢所有帮助或提示！

Answer 1

问题出在您的丢失功能上；均方误差（MSE）对于回归问题很有意义，而在这里您面临一个分类一个（3类），因此损失函数应为Cross Entropy（也称为对数损失）

对于多类分类，也建议不采用S型。因此，从较高的角度来看，以下是建议对您的问题进行一些其他代码修改的地方：

One-hot encode您的3个课程
在最后一层使用softmax激活，该层应该有3个单元（即，与班级数量一样多）

神经网络针对具有不同功能的不同实例做出相同的预测

1 个答案: