我有以下转换矩阵。
n <-10
A<-matrix(0,n,n)
diag(A[-1,]) <-0.5
diag(A[,-1]) <-0.5
A[1,n]<-0.5
A[n,1]<-0.5
答案 0 :(得分:2)
要计算矩阵的幂,可以使用expm
包或matrixcalc
包:
A <- toeplitz(c(1,2,3)) # a square matrix
A
# [,1] [,2] [,3]
# [1,] 1 2 3
# [2,] 2 1 2
# [3,] 3 2 1
library(expm)
A %^% 2
# [,1] [,2] [,3]
# [1,] 14 10 10
# [2,] 10 9 10
# [3,] 10 10 14
library(matrixcalc)
matrix.power(A, 2)
# [,1] [,2] [,3]
# [1,] 14 10 10
# [2,] 10 9 10
# [3,] 10 10 14
对于情节:
powers <- 0:8
Apowers <- lapply(powers, function(k) A %^% k)
norms <- sapply(Apowers, norm, type = "1")
plot(powers, norms)