如何从PHP关联数组中获取确切的输出

时间：2019-02-28 09:51:13

标签： php

我正在尝试在关联数组上使用foreach循环创建html表。这里是有关数组的更多详细信息。

 <?php
$assoc_array = array(
    "0" => array(
        "project_id" => "1",
        "emp_id" => "123",
        "emp_name" => "Max",
        "project" => "Java"        
    ),
    "1" => array(
        "project_id" => "2",
        "emp_id" => "123",
        "emp_name" => "Max",
        "project" => "Java"        
    ),
    "2" => array(
        "project_id" => "3",
        "emp_id" => "124",
        "emp_name" => "Max",
        "project" => "Java"        
    ),
    "3" => array(
        "project_id" => "4",
        "emp_id" => "124",
        "emp_name" => "Max",
        "project" => "Java"        
    ),

    "4" => array(
        "project_id" => "5",
        "emp_id" => "125",
        "emp_name" => "Max",
        "project" => "Java"        
    ),

    "5" => array(
        "project_id" => "6",
        "emp_id" => "125",
        "emp_name" => "Max",
        "project" => "Java"        
    )
)

?>

enter image description here enter image description here enter image description here

所以我试图将它们与他们的emp_id分组。 为此，我正在尝试使用以下逻辑

      <?php
        $assoc_array = array(
            "0" => array(
                "project_id" => "1",
                "emp_id" => "123",
                "emp_name" => "Max",
                "project" => "Java"
            ),
            "1" => array(
                "project_id" => "2",
                "emp_id" => "123",
                "emp_name" => "Max",
                "project" => "Java"
            ),
            "2" => array(
                "project_id" => "3",
                "emp_id" => "124",
                "emp_name" => "Anna",
                "project" => "Angular"
            ),
            "3" => array(
                "project_id" => "4",
                "emp_id" => "124",
                "emp_name" => "Anna",
                "project" => "PHP"
            ),

            "4" => array(
                "project_id" => "5",
                "emp_id" => "125",
                "emp_name" => "John",
                "project" => "Java"
            ),

            "5" => array(
                "project_id" => "6",
                "emp_id" => "125",
                "emp_name" => "John",
                "project" => "Java"
            )
            );
        $prevEmpid = '';
    $tableData = '';
    $tableStartTag = "<table>";
    $tableEndTag = "</table>";
    $wholeData  = "";
    $trFixed  = "<tr><td>project id </td><td>emp id </td><td>emp name</td><td>project</td></tr>";

    foreach($assoc_array as $val) {
         if($val['emp_id'] !== $prevEmpid ) {
             if($tableData) {
                 $wholeData  = $tableStartTag . $trFixed . $tableData . $tableEndTag;
                echo $tableData;
            }
            $wholeData = '';
            $tableData = '';

            $prevEmpid = $val['emp_id'];
        } 
        $tableData .= "<tr><td>" . $val['project_id'] . "</td>"
            . "<td>" . $val['emp_id'] . "<td>" 
            . "<td>" . $val['emp_name'] . "<td>"
            . "<td>" . $val['project'] . "<td></tr>";
    }

但是问题是，因为我没有得到最后一个表数据，因为foreach循环中的元素经历了else条件。

任何小小的帮助都非常感谢。

5 个答案:

答案 0 :(得分：1)

你说

  

但是问题是，自从我没有得到最后的表数据以来，   foreach循环中的元素经历else条件

这是因为这里的这段代码将$prevEmpid设置为当前迭代之一。

if($val['emp_id'] !== $prevEmpid ) {
    if($tableData) {
        echo $tableData;
    }
    $tableData = '';

    $prevEmpid = $val['emp_id'];

} else {
    $tableData .= 'some code to create table with data ';
}

最后一项不会显示，因为它们的emp_id与您的代码所指定的完全相同。

"4" => array(
    "project_id" => "5",
    "emp_id" => "125",
    "emp_name" => "John",
    "project" => "Java"
),

"5" => array(
    "project_id" => "6",
    "emp_id" => "125",
    "emp_name" => "John",
    "project" => "Java"
)

答案 1 :(得分：1)

您丢失了一些项目，因为仅在id更改时才添加输出数据（$ tableData。=）。完全删除其他运算符。并在循环后添加echo以输出最后一组。

demo

但是，您可以通过简单的代码对数组进行分组

$new = [];
foreach($assoc_array as $val) {
    $new[$val['emp_id']][] = $val;
}

然后通过另一个循环输出每个组

答案 2 :(得分：1)

我假设您希望多个表按emp_id分组。

解决方案是，首先需要将 emp_id 划分为数组组。之后，使用for循环创建多个表。

以下是按 emp_id

对数组进行分组的代码 
<?php
$projects = [
        [
            'project_id' => '1',
            'emp_id' => '123',
            'emp_name' => 'Max',
            'project' => 'Java'
        ],
        [
            'project_id' => '2',
            'emp_id' => '123',
            'emp_name' => 'Max',
            'project' => 'Java'
        ],
        [
            'project_id' => '3',
            'emp_id' => '124',
            'emp_name' => 'Max',
            'project' => 'Java'
        ],
        [
            'project_id' => '4',
            'emp_id' => '124',
            'emp_name' => 'Max',
            'project' => 'Java'
        ],

        [
            'project_id' => '5',
            'emp_id' => '125',
            'emp_name' => 'Max',
            'project' => 'Java'
        ],

        [
            'project_id' => '6',
            'emp_id' => '125',
            'emp_name' => 'Max',
            'project' => 'Java'
        ]
        ];

    $empGroups = [];
    foreach ($projects as $project) {
        $empGroups[$project['emp_id']][] = $project;
    }
?>

并创建这样的html表。

<?php foreach ($empGroups as $empGroup) { ?>
<table>
    <tr>
        <td>project_id</td>
        <td>emp_id</td>
        <td>emp_name</td>
        <td>project</td>
    </tr>

    <?php foreach ($empGroup as $pjs) { ?>
    <tr>
        <?php foreach ($pjs as $pj) { ?>

        <td>

            <?php echo $pj?>
        </td>
        <?php } ?>

    </tr>
    <?php } ?>

</table>
<?php } ?>

demo

答案 3 :(得分：1)

<?php
// given following array:
$assoc_array = array(
    "0" => array(
        "project_id" => "1",
        "emp_id" => "123",
        "emp_name" => "Max",
        "project" => "Java"
    ),
    "1" => array(
        "project_id" => "2",
        "emp_id" => "123",
        "emp_name" => "Max",
        "project" => "Java"
    ),
    "2" => array(
        "project_id" => "3",
        "emp_id" => "124",
        "emp_name" => "Anna",
        "project" => "Angular"
    ),
    "3" => array(
        "project_id" => "4",
        "emp_id" => "124",
        "emp_name" => "Anna",
        "project" => "PHP"
    ),

    "4" => array(
        "project_id" => "5",
        "emp_id" => "125",
        "emp_name" => "John",
        "project" => "Java"
    ),

    "5" => array(
        "project_id" => "6",
        "emp_id" => "125",
        "emp_name" => "John",
        "project" => "Java"
    )
    );
// you can create function to display table groupings
function print_table($arr){
$prevEmpid = '';
$tableData = '';

$header = "<tr>
        <td>project_id</td><td>emp_id</td><td>emp_name</td><td>project</td>
</tr>";
$temp = '';

echo '<table>',"\n";

foreach($arr as $val) {
// comparing current value of $val['emp_id'] with $temp
if ($val['emp_id'] != $temp) {
        $tableData .= $header;
}

$tableData .= "\n<tr>\n\t<td>".$val['project_id']."</td>";
$tableData .= '<td>'.$val['emp_id']."</td>";
$tableData .= '<td>'.$val['emp_name']."</td>";
$tableData .= '<td>'.$val['project']."</td>\n</tr>\n";
// save current value of $val['emp_id'] in temp 
$temp = $val['emp_id'];
}

echo $tableData,"</table>\n";
}

print_table($assoc_array);

查看实时代码here

答案 4 :(得分：0)

这是我为最后一行实现逻辑以完成html表格式的方式。 

$prevEmpid = '';
$tableData = '';
$tableStartTag = "<table>";
$tableEndTag = "</table>";
$wholeData  = "";
$trFixed  = "<tr><td>project id </td><td>emp id </td><td>emp name</td><td>project</td></tr>";

foreach($assoc_array as $val) {
     if($val['emp_id'] !== $prevEmpid ) {
         if($tableData) {
             $wholeData  = $tableStartTag . $trFixed . $tableData . $tableEndTag;
            echo $tableData;
        }
        $wholeData = '';
        $tableData = '';

        $prevEmpid = $val['emp_id'];
    } 
    $tableData .= "<tr><td>" . $val['project_id'] . "</td>"
        . "<td>" . $val['emp_id'] . "<td>" 
        . "<td>" . $val['emp_name'] . "<td>"
        . "<td>" . $val['project'] . "<td></tr>";
}
if($tableData) {
             $wholeData  = $tableStartTag . $trFixed . $tableData . $tableEndTag;
            echo $tableData;
        }
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