我的问题标题似乎已经存在,但这是我的完整情况。
我有一个针对基于Map的操作的活动,其中沿着一条道路绘制一条折线,可以说两个位置之间的路线。基本上,该应用会跟踪用户的当前位置(乘车旅行)。因此,直到零件一切正常为止,例如正确显示了路线,设备Location API正在提供位置更新(有点准确),而且我还能够顺利地更改位置更新,
问题是,位置更新有时会呈锯齿状,有时可能不会碰到道路,位置更新会遍及整个地方。
我也研究了ROAD api,但是即使从以前的一些问题中也无法获得正确的帮助。
是否可以使标记仅沿道路移动?
任何帮助将不胜感激。
答案 0 :(得分:1)
您可以通过将标记投影到最近的路径段来将标记捕捉到路径。您可以通过PolyUtil.isLocationOnPath()
找到最近的细分:
PolyUtil.isLocationOnPath(carPos, segment, true, 30)
和标记到该段的投影,您可以通过将测地线的球面坐标转换为正交的屏幕坐标,然后计算投影的正交坐标并将其转换回球面(WGS84 LatLng -> Screen x,y -> WGS84 LatLng
):
Point carPosOnScreen = projection.toScreenLocation(carPos);
Point p1 = projection.toScreenLocation(segment.get(0));
Point p2 = projection.toScreenLocation(segment.get(1));
Point carPosOnSegment = new Point();
float denominator = (p2.x - p1.x) * (p2.x - p1.x) + (p2.y - p1.y) * (p2.y - p1.y);
// p1 and p2 are the same
if (Math.abs(denominator) <= 1E-10) {
markerProjection = segment.get(0);
} else {
float t = (carPosOnScreen.x * (p2.x - p1.x) - (p2.x - p1.x) * p1.x
+ carPosOnScreen.y * (p2.y - p1.y) - (p2.y - p1.y) * p1.y) / denominator;
carPosOnSegment.x = (int) (p1.x + (p2.x - p1.x) * t);
carPosOnSegment.y = (int) (p1.y + (p2.y - p1.y) * t);
markerProjection = projection.fromScreenLocation(carPosOnSegment);
}
具有完整的源代码:
public class MainActivity extends AppCompatActivity implements OnMapReadyCallback {
private GoogleMap mGoogleMap;
private MapFragment mapFragment;
private Button mButton;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mapFragment = (MapFragment) getFragmentManager()
.findFragmentById(R.id.map_fragment);
mapFragment.getMapAsync(this);
mButton = (Button) findViewById(R.id.button);
mButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
}
});
}
@Override
public void onMapReady(GoogleMap googleMap) {
mGoogleMap = googleMap;
mGoogleMap.setOnMapLoadedCallback(new GoogleMap.OnMapLoadedCallback() {
@Override
public void onMapLoaded() {
List<LatLng> sourcePoints = new ArrayList<>();
PolylineOptions polyLineOptions;
LatLng carPos;
sourcePoints.add(new LatLng(-35.27801,149.12958));
sourcePoints.add(new LatLng(-35.28032,149.12907));
sourcePoints.add(new LatLng(-35.28099,149.12929));
sourcePoints.add(new LatLng(-35.28144,149.12984));
sourcePoints.add(new LatLng(-35.28194,149.13003));
sourcePoints.add(new LatLng(-35.28282,149.12956));
sourcePoints.add(new LatLng(-35.28302,149.12881));
sourcePoints.add(new LatLng(-35.28473,149.12836));
polyLineOptions = new PolylineOptions();
polyLineOptions.addAll(sourcePoints);
polyLineOptions.width(10);
polyLineOptions.color(Color.BLUE);
mGoogleMap.addPolyline(polyLineOptions);
carPos = new LatLng(-35.281120, 149.129721);
addMarker(carPos);
mGoogleMap.moveCamera(CameraUpdateFactory.newLatLngZoom(sourcePoints.get(0), 15));
for (int i = 0; i < sourcePoints.size() - 1; i++) {
LatLng segmentP1 = sourcePoints.get(i);
LatLng segmentP2 = sourcePoints.get(i+1);
List<LatLng> segment = new ArrayList<>(2);
segment.add(segmentP1);
segment.add(segmentP2);
if (PolyUtil.isLocationOnPath(carPos, segment, true, 30)) {
polyLineOptions = new PolylineOptions();
polyLineOptions.addAll(segment);
polyLineOptions.width(10);
polyLineOptions.color(Color.RED);
mGoogleMap.addPolyline(polyLineOptions);
LatLng snappedToSegment = getMarkerProjectionOnSegment(carPos, segment, mGoogleMap.getProjection());
addMarker(snappedToSegment);
break;
}
}
}
});
mGoogleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(sourcePoints.get(0), 15));
}
private LatLng getMarkerProjectionOnSegment(LatLng carPos, List<LatLng> segment, Projection projection) {
LatLng markerProjection = null;
Point carPosOnScreen = projection.toScreenLocation(carPos);
Point p1 = projection.toScreenLocation(segment.get(0));
Point p2 = projection.toScreenLocation(segment.get(1));
Point carPosOnSegment = new Point();
float denominator = (p2.x - p1.x) * (p2.x - p1.x) + (p2.y - p1.y) * (p2.y - p1.y);
// p1 and p2 are the same
if (Math.abs(denominator) <= 1E-10) {
markerProjection = segment.get(0);
} else {
float t = (carPosOnScreen.x * (p2.x - p1.x) - (p2.x - p1.x) * p1.x
+ carPosOnScreen.y * (p2.y - p1.y) - (p2.y - p1.y) * p1.y) / denominator;
carPosOnSegment.x = (int) (p1.x + (p2.x - p1.x) * t);
carPosOnSegment.y = (int) (p1.y + (p2.y - p1.y) * t);
markerProjection = projection.fromScreenLocation(carPosOnSegment);
}
return markerProjection;
}
public void addMarker(LatLng latLng) {
mGoogleMap.addMarker(new MarkerOptions()
.position(latLng)
);
}
}
您会得到类似的东西:
但是更好的方法是从路径的起点算起车辆的距离,并通过SphericalUtil.interpolate()
找到它的位置,因为如果多个路径段彼此接近(例如,在同一条道路的不同车道上),如下所示:
与当前汽车位置最接近的“错误”部分。因此,请从路线起点算起汽车的距离,然后使用SphericalUtil.interpolate()
确定路线上的确切点。
答案 1 :(得分:0)
我知道这个问题很旧,但万一有人需要,可以将它添加到Andrii Omelchenko的答案中,这是您可以使用SphericalUtil.interpolate()
在细分上准确找到要点的一种方式:
private LatLng getMarkerProjectionOnSegment(LatLng carPos, List<LatLng> segment, Projection projection) {
Point a = projection.toScreenLocation(segment.get(0));
Point b = projection.toScreenLocation(segment.get(1));
Point p = projection.toScreenLocation(carPos);
if(a.equals(b.x, b.y)) return segment.get(0); // Projected points are the same, segment is very short
if(p.equals(a.x, a.y) || p.equals(b.x, b.y)) return carPos;
/*
If you're interested in the math (d represents point on segment you are trying to find):
angle between 2 vectors = inverse cos of (dotproduct of 2 vectors / product of the magnitudes of each vector)
angle = arccos(ab.ap/|ab|*|ap|)
ad magnitude = magnitude of vector ap multiplied by cos of (angle).
ad = ap*cos(angle) --> basic trig adj = hyp * cos(opp)
below implementation is just a simplification of these equations
*/
float dotproduct = ((b.x-a.x)*(p.x-a.x)) + ((b.y-a.y)*(p.y-a.y));
float absquared = (float) (Math.pow(a.x-b.x, 2) + Math.pow(a.y-b.y, 2)); // Segment magnitude squared
// Get the fraction for SphericalUtil.interpolate
float fraction = dotproduct / absquared;
if(fraction > 1) return segment.get(1);
if(fraction < 0) return segment.get(0);
return SphericalUtil.interpolate(segment.get(0), segment.get(1), fraction);
}