我有一个String
,其值如下:
B/W 0-2 hours of bus start time#*#*B/W 2-9 hours of bus start time#*#*Above 9 hours of bus start time--0%#*#*50%#*#*90%
您如何在split()
上#*#*
?我需要如下输出:
B/W 0-2 hours of bus start time
B/W 2-9 hours of bus start time
Above 9 hours of bus start time
0%
50%
90%
答案 0 :(得分:2)
这样分割字符串:
String mStr = "B/W 0-2 hours of bus start time#*#B/W 2-9 hours of bus start time##Above 9 hours of bus start time--0%##50%##*90%";
Log.e("mStr==", "===" + mStr);
String[] pickList = mStr.split("#\\*#|##|--|##\\*|\\*");
Log.e("pickList==", "===" + pickList.length);
for (int i = 0; i < pickList.length; i++) {
Log.e("pickList==", "===" + pickList[i]);
}
在选择列表内部,您将获得包含拆分数据的输出列表。
答案 1 :(得分:0)
尝试以下-
ct.Counter(words)
答案 2 :(得分:0)
您的字符串应包含相同的定界符。如果您有不同的定界符,则需要预测可以使用哪些定界符,并将这些定界符作为参数传递给由|分隔的split()。签名。
例如,要将#和*符号用作分隔符,则需要这样编写: stringvariable.split(“ \#| \ *”);
答案 3 :(得分:0)
您可以使用单个alternation来匹配1个重复的import pandas as pd
def select_real_product(string_to_elaborate):
return string_to_elaborate.split('+')[0].strip()
df = pd.read_csv("Remarks_Drug.csv", delimiter=',', names=("product", "filename"))
df['product'] = df['product'].apply(select_real_product)
df.to_csv("drug_output100.csv", sep=',', na_rep='empty',index_label=False, index=False)
或匹配#*
--
查看regex demo | Java demo
例如:
(?:#\*)+|--
结果
String s = "B/W 0-2 hours of bus start time#*#*B/W 2-9 hours of bus start time#*#*Above 9 hours of bus start time--0%#*#*50%#*#*90%";
String[] parts = s.split("(?:#\\*)+|--");
for (String part : parts) {
System.out.println(part);
}
答案 4 :(得分:0)
String finalValue =“”; String mystring =“ B / W公交开始时间0-2小时#*# B / W公交开始时间2-9小时##公交开始时间9小时以上- 0%## 50%##* 90%“;
String[] splitSt1 = mystring.split("--");
String detailsString = splitSt1[0];
String percentageString = splitSt1[1];
String[] detailsSt1 = detailsString.split("#\\*#\\*");
String[] percentageSt2 = percentageString.split("#\\*#\\*");
if(detailsSt1.length == detailsSt1.length ){
for(int i=0;i<=(detailsSt1.length-1);i++ )
{
finalValue = finalValue +"* "+ detailsSt1[i]+ "-->" + percentageSt2 [i] +"\n"+"\n";
my_text_view_id.setText(finalValue);
}
}
输出: